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lawyer [7]
4 years ago
5

What process must happen before this process depicted below?

Biology
2 answers:
11Alexandr11 [23.1K]4 years ago
6 0
The answer would be glycolysis.

Glycolysis is what produces the two pyruvate molecules and converts two NAD+ molecules into the two NADH
Snezhnost [94]4 years ago
4 0

Answer:

The correct answer is Glycolysis.

Explanation:

Glycolysis is the partial breakdown of glucose into two pyruvate molecules. This reaction occurs in the cytoplasm of the cell. There is a net generation of 2 NADH and 2 ATP in the process of glycolysis. This pathway occurs in both aerobic and anaerobic conditions.

In anaerobes, it is called fermentation in which two pyruvate is converted into lactate by converting 2 NADH produced during glycolysis into 2 NAD⁺. The release of NAD⁺ than supplied to glycolysis again so that glycolysis keep running.

                       Glucose →  2 pyruvate → 2 lactate              

Therefore, the glycolysis process must take place before two pyruvate molecules are converted to two lactic acid molecules.  

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Flock X
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Answer:

                Total Pieces      Food Percentage   Simulated Number of Birds

              of Food Eaten                                      in Flock for 2nd Generation

Flock X          57                            19%                                 6

Flock Y          153                           51%                                15

Flock Z         90                            30%                                9

<u>Calculations. </u>

Food percentage:

Flock X = 57/300 * 100% = 19%

Flock Y = 153/300 * 100% = 51%

Flock Z = 90/300 * 100% = 30%

Simulated Number of Birds in Flock for 2nd Generation

Flock X = 19% * 30 = 6

Flock Y = 51% * 30 = 15

Flock Z = 30% * 30 = 9

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