A pea plant with round seeds has the genotype rr. if you cross this plant with a wrinkled-seed plant, genotype rr, what is the p
robability that the offspring will have wrinkled seeds?
1 answer:
I think you wrote this wrong? Is it not round rr vs wrinkled RR?? I'll answer it with that assumption:
You are crossing a rr with an RR:
You only get Rr back so they will phenotypically be all wrinkled
If you are crossing rr with an Rr (so a heterozygote wrinkled):
50% will be Rr (wrinkled)
50% will be rr (round)
See my picture for the Punnett Squares for both answers!
You are crossing a rr with an RR:
You only get Rr back so they will phenotypically be all wrinkled
If you are crossing rr with an Rr (so a heterozygote wrinkled):
50% will be Rr (wrinkled)
50% will be rr (round)
See my picture for the Punnett Squares for both answers!
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Answer:
Explanation:
It is given that
B is the dominant allele which represents the black color
and b is the recessive allele which represents the white fur.
B being dominant will result into black color fur for genotype "Bb"
Given -
Frequency of black fur allele (p) is
As per Hardy Weinberg's first law of equilibrium
Substituting the value of p in above equation, we get -
q represents the frequency for white fur allele
Frequency of white fur phenotype is
Frequency of homozygous black fur phenotype (BB) is
As per Hardy Weinberg's second law of equilibrium -
Combined frequency of homozygous and heterozygous black fur phenotype is