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Kazeer [188]
3 years ago
9

Hey guys can u tell me if the top is correct if its not can u show me step by step what to do and what the answer will be and ca

n u guys tell me what explanation I should write in the bottem

Mathematics
1 answer:
ASHA 777 [7]3 years ago
6 0
You have the right idea and you are close to the correct answer. However that's not what your teacher is looking for in terms of steps.

The starting inequality is b + 8 \ge 20
She starts off selling 8 buckets. Then she sells b more to get a total of b+8
This total must be 20 or larger which is why I set b+8 greater than or equal to 20

Solve for b by subtracting 8 from both sides

b + 8 \ge 20

b + 8-8 \ge 20-8

b \ge 12

So she needs to sell at least 12 more buckets to reach her goal

If you graphed this on a number line, then you would draw a closed circle at 12. Then shade to the right of the close circle. 
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The base of a solid is bounded by the curve y = sqrt (x+1) the x-axis and the line x = 1. the cross sections, taken perpendicula
Andrei [34K]

See attached for a sketch of some of the cross sections.

Each cross section has area equal to the square of the side length, which in turn is the vertical distance between the curve y = √(x + 1) and the x-axis (i.e. the distance between them that is parallel to the y-axis). This distance will be √(x + 1).

If the thickness of each cross section is ∆x, then the volume of each cross section is

∆V = (√(x + 1))² ∆x = (x + 1) ∆x

As we let ∆x approach 0 and take infinitely many such cross sections, the total volume of the solid is given by the definite integral,

\displaystyle \int_{-1}^1 (x+1) \, dx = \left(\frac{x^2}2 + x\right) \bigg|_{-1}^1 = \boxed{2} ~~~~ (B)

3 0
2 years ago
20 points!!
ANEK [815]

See below for the proof of the equation \frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)

<h3>How to prove the equation?</h3>

The equation is given as:

\frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b)

Take the LCM

\frac{(ax + by)(x - y) -(ax - by)(x + y)}{(x + y)(x - y)}= 2(a - b)

Expand

\frac{ax^2 - axy + bxy - by^2 -ax^2 - axy + bxy + by^2}{(x + y)(x - y)}= 2(a - b)

Evaluate the like terms

\frac{-2axy + 2bxy }{(x + y)(x - y)}= 2(a - b)

Rewrite as:

\frac{-2axy + 2bxy }{x^2 - y^2}= 2(a - b)

Factorize the numerator

\frac{2(a - b)(x^2 - y^2)}{x^2 - y^2}= 2(a - b)

Divide

2(a - b)= 2(a - b)

Both sides are equal

Hence, the equation \frac{ax + by}{x + y} - \frac{ax - by}{x - y}= 2(a - b) has been proved

Read more about equations at:

brainly.com/question/2972832

#SPJ1

5 0
2 years ago
Help please! make sure to tell me the answer and an explanation!
soldier1979 [14.2K]

Answer: 10

Step-by-step explanation:

So since this is all about perimeter you just got to add the values together. So lets use 12 as the denominator for every fraction. 1/4 is equal to 3/12 and 2/3 is equal to 8/12. So in conclusion 3/12 plus 8/12 and 1/12 will equal 1 in total. and then add up all the whole numbers 4 + 2 + 3 + 1 will get you 10. So 10 is your answer.

Please make me brainliest

8 0
3 years ago
Rochelle works part-time at the college museum, which pays her at a rate of $10 per hour. She also makes small bracelets that sh
katrin [286]
We know for our problem that Rachel makes $10 per hour. Sincex represent the number of hours that she works,  10x will be the total amount that she will make for working x hours. We also know that she sells bracelets for $5 each. Since y represents the number of of bracelets that she sells, 5y will be her total revenue for selling y bracelets. We also know that she needs to earn at least $200 a week to cover her expenses, so the sum of 10x and 5y must be equal or greater than 200:

10x+5 \geq 200

We can conclude that <span>the graphs that shows the inequality that represents this situation, with its solution region shaded is:</span>

4 0
3 years ago
Solve for k 5/8(3k+1)-1/4(7k+2)=1
lesya [120]

Answer:

<h2>k = 7</h2>

Step-by-step explanation:

\dfrac{5}{8}(3k+1)-\dfrac{1}{4}(7k+2)=1\qquad\text{multiply both sides by 8}\\\\8\!\!\!\!\diagup^1\cdot\dfrac{5}{8\!\!\!\!\diagup_1}(3k+1)-8\!\!\!\!\diagup^2\cdot\dfrac{1}{4\!\!\!\!\diagup_1}(7k+2)=8\cdot1\\\\5(3k+1)-2(7k+2)=8\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\(5)(3k)+(5)(1)+(-2)(7k)+(-2)(2)=8\\\\15k+5-14k-4=8\qquad\text{combine like terms}\\\\(15k-14k)+(5-4)=8\\\\k+1=8\qquad\text{subtract 1 from both sides}\\\\k=7

3 0
3 years ago
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