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Novosadov [1.4K]
4 years ago
12

Find two consecutive even integers such that the square of the first decreased by 11 equals 5 times the second.

Mathematics
1 answer:
Dima020 [189]4 years ago
5 0
It is 45 and 67 I remember this from boating school 5 times a second in 11
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What number should be added to both sides of the equation to complete the square? X^2-10=7
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I must assume that you meant   <span>X^2-10x =7.  If that is indeed the case, then:

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Then x = 5 plus or minus 4 sqrt(2) (answers)
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