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3 years ago

Please solve:Common Factors Of Polynomials

Mathematics

2 answers:

EleoNora [17]3 years ago

8 0

The answer is D on e2020

GenaCL600 [577]3 years ago

4 0

1- $8x^2+12x \\ =4x*2x+4x*3 \\ =4x(2x+3) \\ =A$

2- $20mn-30m \\ =10m*2n-10m*3 \\ =10m(2n-3) \\ =B$

3- $15x^3-12x \\ =3x*5x^2-3x*4 \\ =3x(5x^2-4) \\ =B$

4- $12x^2y-3x^2y^2-15xy \\ =3xy*4x-3xy*xy-3xy*5 \\ =3xy(4x-xy-5) \\ =C$

5- $24w^2x^6-8wx^3 \\=8wx^3*3wx^3-8wx^3*1 \\ =8wx^3(3wx^3-1) \\ =D$

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At noodle & company restaurant, the probability that a customer will order a nonalcoholic beverage is .46. Find the probabil

skelet666 [1.2K]

Answer:

0.0021

Step-by-step explanation:

Given:

Probability of ordering a nonalcoholic beverage is, $P(N)=0.46$

Number of samples are $n=10$

Now, the complement of event 'N' is not ordering a nonalcoholic beverage.

Therefore, $P(\overline N)=1-P(N)=1-0.46=0.54$

Now, for a sample of '10' customers, the probability of not ordering a non alcoholic beverage is product of their individual probabilities as all these events are independent events.

Therefore, probability that none of the 10 will order a nonalcoholic beverage is given as:

$=[P(\overline N)]^{10}\\\\=(0.54)^{10}\\\\=0.0021$

5 0

3 years ago

The use of mathematical methods to study the spread of contagious diseases goes back at least to some work by Daniel Bernoulli i

harina [27]

Answer:

$y(t) = y_o e^{\beta t}$

$x(t) = x_o e^{\frac{-\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

Step-by-step explanation:

From the question we are told that

$\frac{dy}{y} = -\beta dt$

Now integrating both sides

$ln y = \beta t + c$

Now taking the exponent of both sides

$y(t) = e^{\beta t + c}$

=> $y(t) = e^{\beta t} e^c$

Let $e^c = C$

$y(t) = C e^{\beta t}$

Now from the question we are told that

$y(0) = y_o$

Hence

$y(0) = y_o = Ce^{\beta * 0}$

=> $y_o = C$

$y(t) = y_o e^{\beta t}$

From the question we are told that

$\frac{dx}{dt} = -\alpha xy$

substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

=> $\frac{dx}{x} = -\alpha y_oe^{-\beta t} dt$

Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

Now taking the exponent of both sides

$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

=> $x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} } e^c$

Let $e^c = A$

=> $x(t) =K e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

Now from the question we are told that

$x(0) = x_o$

$x(0)=x_o =K e^{\alpha \frac{y_o}{\beta } e^{-\beta * 0} }$

=> $x_o = K e^{\frac {\alpha y_o }{\beta } }$

divide both side by $(K * x_o)$

=> $K = x_o e^{\frac {\alpha y_o }{\beta } }$

$x(t) =x_o e^{\frac {-\alpha y_o }{\beta } } * e^{\alpha \frac{y_o}{\beta } e^{-\beta t} }$

=> $x(t)= x_o e^{\frac{-\alpha * y_o }{\beta} + \frac{\alpha y_o}{\beta } e^{-\beta t} }$

=> $x(t) = x_o e^{\frac{\alpha y_o }{\beta }[e^{-\beta t} - 1] }$

Generally as t tends to infinity , $e^{- \beta t}$ tends to zero

$\lim_{t \to \infty} x(t) = x_oe^{\frac{-\alpha y_o}{\beta } }$

5 0

3 years ago

I need someone to help me do this, see attached documents for the questions

Brilliant_brown [7]

Answer:

1.) 20.2

Step-by-step explanation:

1.) You need to use the distance formula:

$d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Find the distance of A to B first:

$(-2,2)(3,2)\\\\\sqrt{(3+2)^2+(2-2)^2}\\\\\sqrt{(5)^2+(0)^2}\\\\\sqrt{25} =5$

B to C:

$(3,2)(-1,-5)\\\\\sqrt{(-1-3)^2+(-5-2)^2}\\\\\sqrt{(-4)^2+(-7)^2}\\\\\sqrt{16+49}\\\\\sqrt{65} =8.06=8.1$

C to A:

$(-1,-5)(-2,2)\\\\\sqrt{(-2+1)^2+(2+5)^2}\\\\\sqrt{(-1)^2+(7)^2}\\\\\sqrt{1+49}\\\\\sqrt{50}=7.07=7.1$

Add distances to find the perimeter:

$5+8.1+7.1=20.2$

2.) Part A:

You need to use the mid-point formula:

$midpoint=(\frac{x_{1}+x_{2}}{2} ,\frac{y_{1}+y_{2}}{2} )$

$(3,2)(7,11)\\\\(\frac{3+7}{2},\frac{2+11}{2})\\\\(\frac{10}{2},\frac{13}{2})\\\\m=( 5,6.5)$

Part B:

1. Use the slope-intercept formula:

$y=mx+b$

M as the slope, b the y-intercept.

Find the slope of the two points A and B using the slope formula:

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}} =\frac{rise}{run}$

Insert slope as m into equation.

Take point A as coordinates $(x,y)$ and insert into the equation. Solve for the intercept, b:

$(y)=m(x)+b$

Insert the value of b into the equation.

2. Use the mid-point coordinate. Take the slope.

If you need to find the perpendicular bisector, you will take the negative reciprocal of the slope. Switch the sign and flip it. Ex:

$\frac{1}{2} =-\frac{2}{1}=-2\\$

Insert the new slope into the slope-intercept equation as m.

Take the mid-point coordinate as (x,y) and insert into the equation with the new points. Solve for b.

Insert the value of b.

4 0

3 years ago

45 points! x+1(8+5)+y2-3(x3+y-4)=36-4+x7-y-1 pls i need help now!

Nadya [2.5K]

The answer is X=-2/5

3 0

2 years ago

I need helpp please

IrinaK [193]

Answer:

Total is $138.75 which is answer D

Step-by-step explanation:

15*3.5= $52.50

15*5.75= $86.25

Total is $138.75

3 0

3 years ago

Read 2 more answers