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3 years ago

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A formula has been developed from the observations that you have made . See if you can identify the parts of the equations.since

this formula for graphing uses the slope and the y - intercept , it’s called slope intercept form Y =Mx +6

1 answer:

earnstyle [38]3 years ago

7 0

M is the slope of the graph where as 6 is the y-intercept value.

Step-by-step explanation:

The slope intercept form follow the format of y=mx+c where m is the slope of the graph, and c is the y-intercept of the graph.

In this question,the formula is Y=Mx+6 where M is the slope of the graph and 6 is the y-intercept of the graph.

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Slope intercept form : brainly.com/question/10676927

Keyword : slope intercept form

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An equal lateral triangle with a perimeter of 15 units is graft on according to grade the triangle is dilated by scale factor of

inysia [295]

Answer:

(0.25x, 0.25y)

Step-by-step explanation:

Since the origin is the center of the scale factor of dilation, we don't need to add or subtract anything

Multiplying the x and y values of the ordered pair by 0.25 represents what the value would be with the scale factor, meaning multiplication.

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3 years ago

Vito avido is a sales representative for a company that sells roofing material. he receives a graduated commission of 5 percent

nexus9112 [7]

23458 >20000

Hence commission will be 7%

$\\ \rm\longmapsto 23458\times \dfrac{7}{100}$

$\\ \rm\longmapsto \dfrac{164206}{100}$

$\\ \rm\longmapsto 1642.06$

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3 years ago

Read 2 more answers

I need help answering this ASAP

Leokris [45]

Answer:

x greater than and equal to -7

Step-by-step explanation:

Parabola touches at -7 and is going straight towards all positive integers

Therefore the domain is all numbers greater than or equal to -7

8 0

3 years ago

Tessa had $35. She bought a book for $7 and a magazine for $5. Which expression correctly shows the total money Tessa has left?

serious [3.7K]

<span>$35 + (−$7) + (−$5) is the correct answer involving your question. </span>

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4 years ago

Read 2 more answers

. Lightning Strikes It has been said that the probability of being struck by lightning is about 1 in 750,000, but under what cir

mrs_skeptik [129]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

$P(U |D ) = 0.198$

b

$P(O\ n \ B) = 0.188$

c

$P(O | B) = 0.498$

Step-by-step explanation:

The total number of deaths is mathematically represented as

$T = 16 + 23 + \cdots + 16$

$T =623$

The total number of deaths in 1996 - 2000 is mathematically represented as

$T_a = 16 + 23+ \cdots + 30$

$T_a = 235$

The total number of deaths in 2001 - 2005 is mathematically represented as

$T_b = 17 + 16 + \cdots + 23$

$T_b = 206$

The total number of deaths in 2006 - 2010 is mathematically represented as

$T_c = 15 + 17 + \cdots + 16$

$T_d = 182$

Generally the the probability that it would occur under the tree given that the death was after 2000 is mathematically represented as

$P(U |D ) = \frac{P(A \ n\ U )}{P(A)}$

Here $P(A \ n\ U )$ represents the probability that it was after 2000 and it was under the tree and this is mathematically represented as

$P(A \ n\ U ) = \frac{Z}{ T}$

Here Z is the total number of death under the tree after 2000 and it is mathematically represented as

$Z = 35 + 42$

=> $Z = 77$

=> $P(A \ n\ U ) = \frac{77}{ 623}$

=>

Also

$P(A)$ is the probability of the death occurring after 2000 and this is mathematically represented as

$P(A) = \frac{T_b + T_c}{ T}$

=> $P(A) = \frac{ 206+ 182}{623}$

=>

So

$P(U |D ) = \frac{\frac{77}{ 623} }{ \frac{ 206+ 182}{623}}$

=> $P(U |D ) = 0.198$

Generally the probability that the death was from camping or being outside and was before 2001 is mathematically represented as

$P(O | B) = \frac{T_z}{ T}$

Here $T_z$ is the total number of death outside / camping before 2001 and the value is 117

So

$P(O \ n \ B) = \frac{117}{623}$

=> $P(O\ n \ B) = 0.188$

Generally the probability that the death was from camping or being outside given that it was before 2001 is mathematically represented as

$P(O | B) = \frac{ P( O \ n \ B)}{ P(B)}$

Here $P(B)$ is the probability that it was before 2001 , this is mathematically represented as

$P(B ) = \frac{T_a}{T}$

=> $P(B ) = \frac{235}{623}$

So

$P(O | B) = \frac{ \frac{117}{623}}{ \frac{235}{623}}$

=> $P(O | B) = 0.498$

5 0

3 years ago