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2 years ago

Can you answer my question Hypotenuse=

Mathematics

1 answer:

notsponge [240]2 years ago

8 0

Answer is 50
Reason
Using Pythagorean theory
a^2 + b^2 = c^2
a and b are the legs, the hypotenuse is c
14^2 + 48^2 = c^2
2500 = c^2
Now take the square root of both sides
50 = c

You might be interested in

If 8 people do a job in 40 hours. How many people need to do the job in 32 hours?

bija089 [108]

Answer:

6 people

Step-by-step explanation:

8/40 = x/32

multiply both sides by 32: 8(32)/40 = x

x = 256/40

= 6.4

≈ 6

8 0

3 years ago

Can someone please answer. There is one problem. There's a picture. Thank you!

laila [671]

The answer is D, or 168.
The cheese can be any one out of 3 = 3 choices. For each of those . . .
The first topping can be any one of 8. For each of those . . .
The second topping can be any one of the remaining 7 . For each of those . . .
The third topping can be any one of the remaining 6 .

Total number of ways to assemble a pizza = (3 x 8 x 7 x 6) = 1,008 ways.

<span>BUT . . . </span>

You could choose the SAME 3 toppings in (3 x 2) = 6 different ways, and
nobody could tell the difference once they were selected. All 6 different
ways would result in the same pizza.

So, out of the 1,008 total different ways there are of choosing ingredients,
<span>there are only ( 1,008 / 6 ) = </span>168<span> different and distinct pizzas.</span>

3 0

3 years ago

Read 2 more answers

Answer this correctly for brainliest pls!!

Molodets [167]

A function that depicts depreciation can be represented as equations, graphs and tables.

<h3>The yearly value of each car for the first five years</h3>

The functions are given as:

$V(t) =C(1 - r^t)$

$V(t) =C(1 - r)^t$

Where:

C = 5895 --- the initial value of the car

r = 22% --- the rate of depreciation

For the first 5 years, the values of t = 1, 2, 3, 4 and 5

For the first function, we have:

$V(1) =5895(1 - 22\%^1) = 4598.1$

$V(2) =5895(1 - 22\%^2) = 5609.7$

$V(3) =5895(1 - 22\%^3) = 5832.2$

$V(4) =5895(1 - 22\%^4) = 5881.2$

$V(5) =5895(1 - 22\%^5) = 5892.0$

For the second function, we have

$V(1) =5895(1 - 22\%)^1 = 4598.1$

$V(2) =5895(1 - 22\%)^2 = 3586.5$

$V(3) =5895(1 - 22\%)^3 = 2797.5$

$V(4) =5895(1 - 22\%)^4 =2182.0$

$V(5) =5895(1 - 22\%)^5 = 1702.0$

So, the table of values is:

$\left[\begin{array}{ccc}Years&Car\ 1&Car\ 2\\1&4598.1&4598.1\\2&5609.7&3586.5\\3&5832.2&2797.5\\4&5881.2&2182.0\\5&5892.0&1702.0\end{array}\right]$

See attachment for the graphs of the two functions

<h3>Interpreting the graphs</h3>

The graph of car 1 increases up to C(t) = 5895, and then remains constant as the value of t increases while the graph of car 2 follows an exponential pattern.

This means that, the graph 2 that follows an exponential pattern is more realistic

<h3>The worth of the cars after 5 years</h3>

From the table, the worth of car 1 is $5892.0, while the worth of car 1 is $1702.0

Read more about graphs and functions at:

brainly.com/question/13473114