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lisabon 2012 [21]
3 years ago
9

Find the measure of the indicated angle to the nearest degree

Mathematics
1 answer:
Alisiya [41]3 years ago
3 0

Answer:

The answer to your question is below

Step-by-step explanation:

14) sin Ф = 32/33

    sin Ф = 0.9697

        Ф = 75.86°

15) sin Ф = 16/36

     sin Ф = 0.444

          Ф = 26.39°

16) sin Ф = 29/36

     sin Ф = 0.806

          Ф = 53.66°

17) cos Ф = 11/34

    cos Ф = 0.324

          Ф = 71.12°

18) sin Ф = 21/40

     sin Ф = 0.525

           Ф = 31.67°

19) cos Ф = 6/14

     cos Ф = 0.429

          Ф = 64.62°

20) cos Ф = 38/39

      cos Ф = 0.974

            Ф = 13°

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Find the angle between u = (-2,-5) and v = (5,2)
OleMash [197]

The angle between u = (-2,-5) and v = (5,2) is 134 degrees approximately.

<u>Solution:</u>

Given, two vectors are u = (-2, -5) and v = (5, 2)

We have to find the angle between two vectors.

We know that,

a. b=\|a\| .\|b\| \times \cos \theta

where \theta is angle between vectors a and b

\text { Now vectors are }(-2 \vec{\imath}-5 \vec{\jmath}) \text { and }(5 \vec{\imath}+2 \vec{\jmath})

(-2 \vec{\imath}-5 \vec{\jmath}) \cdot(5 \vec{\imath}+2 \vec{\jmath})=\sqrt{(-2)^{2}+(-5)^{2}} \times \sqrt{5^{2}+2^{2}} \times \cos \theta

\text { since }\|a\|=\sqrt{x^{2}+y^{2}} \text { for } a=x \vec{\imath}+y \vec{\jmath}

\begin{array}{l}{-10-10=\sqrt{29} \times \sqrt{29} \times \cos \theta} \\\\ {-20=29 \times \cos \theta} \\\\ {\cos \theta=\frac{-20}{29}} \\\\ {\theta=\cos ^{-1} \frac{-20}{29}} \\\\ {\theta=133.60}\end{array}

Hence, the angle between given two vectors is 134 degrees approximately.

3 0
3 years ago
Could someone help plz
Komok [63]

Answer:

The radius of the sphere is approximately 62.71 cm

Step-by-step explanation:

The question relates to the definition of a sphere

The given parameters are;

The distance between the sharp parallel blades through which the sphere is rolled = 77 centimeters

The radii of the circular faces left by cutting the sphere with the blade = 39 cm  and 60 cm

From the triangles formed by the cross-section of the sphere, we have;

AB ║ DE Given

∠A ≅ ∠E, ∠D ≅ ∠B Alternate angles

∠C ≅ ∠C by reflective  property

∴ ΔABC ~ ΔDCE by Angle-Angle similarity theorem

CF/CG = AB/DE = 78/120 = 13/20

CF = CG × 13/20

CF + CG = 77

∴ CG × 13/20 + CG = 77

33·CG/20 = 77

∴ CG = 140/3

CF = 13/20 × CG = 13/20 × 140/3 = 91/3

CF = 91/3

The diameter of the sphere AE = AC + EC

By Pythagoras's theorem

AC = √(FA² + CF²) = √(39² + (91/3)²) = 13·√(130)/3

EC = √(CG² + GD²) = √((140/3)² + 60²) = 20·√(130)/3

∴ AE = AC + EC = 13·√(130)/3 + 20·√(130)/3 = 11·√(130)

The diameter, 'D', of the sphere, AE = 11·√(130)

The radius of the sphere = D/2 = 11·√(130)/2 ≈ 62.71 cm

7 0
2 years ago
The high temperature is forecast to be 5.4 F . What is this temperature in degrees Celsius ()?
AleksAgata [21]

Answer:

-14c

Step-by-step explanation:

I’m using the actual values 1F = -17C so just times that by 5.4

7 0
3 years ago
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Allisa [31]

Standard form

6x+5x-8 =-41

Is in standard form

6 0
3 years ago
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Likurg_2 [28]

Answer:

Step-by-step explanation:

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50/20 plus 72/20 plus 55/20

177/20 would be your answer

3 0
3 years ago
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