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sergey [27]
2 years ago
13

If a polygon is drawn inside a circle, we say that the? A. polygon is tangent to the circle B. circle is inscribed in the polygo

n C. polygon circumscribes the circle D. circle circumscribes the polygon
Mathematics
2 answers:
Aneli [31]2 years ago
7 0

Answer:

D. circle circumscribes the polygon

Step-by-step explanation:

cause the polygon is inside the circle

Serga [27]2 years ago
3 0
Answer is D since the polygon is inside the circle !!!
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let x1,x2, and x3 be linearly independent vectors in R^(n) and let y1=x2+x1; y2=x3+x2; y3=x3+x1. are y1,y2,and y3 linearly indep
Nutka1998 [239]

Answer with Step-by-step explanation:

We are given that

x_1,x_2 and x_3 are linearly independent.

By definition of linear independent there exits three scalar a_1,a_2 and a_3 such that

a_1x_1+a_2x_2+a_3x_3=0

Where a_1=a_2=a_3=0

y_1=x_2+x_1,y_2=x_3+x_2,y_3=x_3+x_1

We have to prove that y_1,y_2 and y_3 are linearly independent.

Let b_1,b_2 and b_3 such that

b_1y_1+b_2y_2+b_3y_3=0

b_1(x_2+x_1)+b_2(x_3+x_2)+b_3(x_3+x_1)=0

b_1x_2+b_1x_1+b_2x_3+b_2x_2+b_3x_3+b_3x_1=0

(b_1+b_3)x_1+(b_2+b_1)x_2+(b_2+b_3)x_3=0

b_1+b_3=0

b_1=-b_3...(1)

b_1+b_2=0

b_1=-b_2..(2)

b_2+b_3=0

b_2=-b_3..(3)

Because x_1,x_2 and x_3 are linearly independent.

From equation (1) and (3)

b_1=b_2...(4)

Adding equation (2) and (4)

2b_1==0

b_1=0

From equation (1) and (2)

b_3=0,b_2=0,b_3=0

Hence, y_1,y_2 and y_3 area linearly independent.

5 0
2 years ago
Alex has a rectangle piece of red paper that is 4 centimeter wide .its length is twice it's width she glues a piece of paper blu
xenn [34]
4cm•2=8cm which is the length of the red paper so therefore Red paper= 4cmx8cm.
Then your going to take 3cm-4cm= 1cm
Next your going to solve for 7cm-8cm=1cm
Which leaves you with an answer of 1cmx1cm more of visible red paper.
8 0
3 years ago
Answer this question
Murljashka [212]

Answer:

a = p * q

b = p * s + q * r

c = r * s

Step-by-step explanation:

In the trinomial ax² + bx + c

a is the coefficient of x²

b is the coefficient of x

c is the numerical term

∵ The trinomial is ax² + bx + c

∵ Its factors are (px + r) and (qx + s)

∴ ax² + bx + c = (px + r)(qx + s)

∵ (px + r)(qx + s) = (px)(qx) + (px)(s) + r(qx) + (r)(s)

∴ (px + r)(qx + s) = pqx² + (psx + qrx) + rs

∴ ax² + bx + c = pqx² + (ps + qr)x + rs

→ By comparing the two sides

∵ ax² = pqx² ⇒ divide both sides by x²

∴ a = pq

∵ bx = (ps + qr)x ⇒ Divide both sides by x

∴ b = ps + qr

∴ c = rs

∴ a = p * q

∴ b = p * s + q * r

∴ c = r * s

5 0
2 years ago
the ordered pair for point M is (2, -4). Explain how you would rotate point M 270 degrees clockwise and find the ordered pair of
vodomira [7]

Answer:

3 is the answer

Step-by-step explanation:

6 0
3 years ago
Which point is the same distance from the y-axis but on the opposite side of the y-axis as point C?
bixtya [17]

Answer: The answer would be 5.2

Step-by-step explanation:

5 0
3 years ago
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