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3 years ago

Solve for x. See attachment.....

Mathematics

1 answer:

N76 [4]3 years ago

8 0

64=-4+4x
64+4=4x
68=4x
68/4=x
17=x

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A frequency table of grades has five classes (A, B, C, D,F) with frequencies of 4, 10, 17, 6, and respectively. Using percentage

fiasKO [112]

We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:

$\begin{gathered} N=4+10+17+6+2 \\ N=39 \end{gathered}$

We have then a total number of grades of 39.

The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.

Then, for grade A, the relative frequency (RF) will be:

$RF_A=\frac{4}{39}\approx0.10256\approx10.26\text{ \%}$

This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.

Now, to complete the table we do the same for the other frequencies:

For grade B:

$RF_B=\frac{10}{39}\approx0.2564\approx25.64\text{ \%}$

For grade C:

$RF_C=\frac{17}{39}\approx0.4359\approx43.59\text{ \%}$

For grade D:

$RF_D=\frac{6}{39}\approx0.1538\approx15.38\text{ \%}$

For grade F:

$RF_D=\frac{2}{39}\approx0.0513\approx5.13\text{ \%}$

4 0

11 months ago

According to police sources, a car with a certain protection system will be recovered 87% of the time. Find the probability that

WITCHER [35]

Answer: 0.01145

Step-by-step explanation:

We use Binomial distribution , where the probability of getting x successes in n trial is given by :-

$P(x)=^nC_xp^x(1-p)^{n-x}$ , p = probability of getting each success in each trial.

As per given

The proportion that a car with a certain protection system will be recovered= p=0.87

n= 8

Let x be the number of cars will be recovered.

Then, the probability that 4 of 8 stolen cars will be recovered:

$P(X=4)=^8C_4(0.87)^4(1-0.87)^{8-4}$

$=\dfrac{8!}{4!(8-4)!}(0.87)^4(0.13)^4\\\\= 70(0.57289761)(0.00028561)\\\\=0.0114537700474\approx0.01145$

Hence, the required probability is 0.01145.

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