Given:
It is given that,
PQ ⊥ PS and
∠QPR = 7x-9
∠RPS = 4x+22
To find the value of ∠QPR.
Formula
As per the given problem PR lies between PQ and PS,
So,
∠QPR+∠RPS = 90°
Now,
Putting the values of ∠RPS and ∠QPR we get,
or, 
or, 
or, 
or, 
Substituting the value of in ∠QPR we get,
∠QPR = 
or, ∠QPR = 
Hence,
The value of ∠QPR is 40°.
Answer: 8 Units
btw have a good day :)
the answer is
d. rational
Answers:
- x = 11
- angle RQS = 106 degrees
- angle SQT = 74 degrees
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Explanation:
Straight angles are always 180 degrees in measure.
The two smaller angles shown add up to 180
(angle RQS) + (angle SQT) = angle RQT
(9x+7) + (6x+8) = 180
(9x+6x) + (7+8) = 180
15x+15 = 180
15x = 180-15
15x = 165
x = 165/15
x = 11
From here, we then know that,
- angle RQS = 9x+7 = 9*11+7 = 99+7 = 106 degrees
- angle SQT = 6x+8 = 6*11+8 = 66+8 = 74 degrees
Note how the two results add to 106+74 = 180 to help confirm the answers.
Answer:
Prob = 0.00009 = 0.009% , Less Likely
Step-by-step explanation:
Using Binomial Distribution, Prob = N c r . ( P )^ r . ( Q ) ^ (n -r) .
,P = success probability, ie candidate considered be trustworthy = 70% = 0.7; N = trials = 200 ; Q = failure probability, ie non trustworthy = 1 - 0.7 = 0.3 r = no. of success = 116
Pr = 200c116 . (0.7)^116 . (0.3)^(200 - 116) = 200c116 (0.7)^116 (0.3)^84 = 0.00009 = 0.009%
Less probability means Less Likely
