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3 years ago

One egg carton holds 12 eggs how many cartons are you able to fill with 60 eggs

Mathematics

2 answers:

PtichkaEL [24]3 years ago

8 0

The answer should be 5 egg cartons

Pachacha [2.7K]3 years ago

8 0

You can fill 5 cartons with 60 eggs because 60 divided by 12 is 5. Hope i helped!

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WILL UPVOTE EVERY ANSWER! A MULTIPLE CHOICE QUESTION!

defon

I believe the answer is C.

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4 years ago

Jacksons kitty weighed 2 pounds and 3 ounces a month later the kitty weighed 56 ounces how much weight did the kitty gain in tha

8_murik_8 [283]

Answer:

21 ounces

Step-by-step explanation:

2 pounds→ convert to ounces= 32

32 ounces+ 3 ounces= 35

56 ounces-35 ounces= 21 ounces

6 0

3 years ago

Read 2 more answers

Jack had 50 coins in nickels and quarters. He has 8 more nickels than quarters. How many nickles did Jack have?

Leokris [45]

50-8 = 42
42/2 = 21
21+8= 29

Nickels-29
Quarters-21

Double Check
29+21 = 50

6 0

3 years ago

I need help PLSS!! for math.Its due tomorow

PSYCHO15rus [73]

Answer:

3 and 4

Step-by-step explanation:

those are the only numbers multiplied that equal 12

8 0

3 years ago

Write the point-slope form of an equation of the line through the points (-4, 7) and (5, 3).

cupoosta [38]

Answer:

$y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x+4)$

$y-3=-\frac{\displaystyle 4}{\displaystyle 9}(x-5)$

Step-by-step explanation:

Hi there!

Point-slope form: $y-y_1=m(x-x_1)$ where $m$ is the slope and $(x_1,y_1)$ is a point that falls on the line

1) Determine the slope (m)

$m=\frac{\displaystyle y_2-y_1}{\displaystyle x_2-x_1}$ where two given points are $(x_1,y_1)$ and $(x_2,y_2)$

Plug in the given points (-4, 7) and (5, 3):

$m=\frac{\displaystyle 3-7}{\displaystyle 5-(-4)}\\\\m=\frac{\displaystyle 3-7}{\displaystyle 5+4}\\\\m=\frac{\displaystyle -4}{\displaystyle 9}$

Therefore, the slope of the line is $-\frac{\displaystyle 4}{\displaystyle 9}$ . Plug this into $y-y_1=m(x-x_1)$ as $m$ :

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

2) Plug a point into $y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)$

Because we're given two points, there are two ways we can write this equation:

$y-y_1=-\frac{\displaystyle 4}{\displaystyle 9}(x-x_1)\\\\y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x-(-4))\\\\y-7=-\frac{\displaystyle 4}{\displaystyle 9}(x+4)$

$y-3=-\frac{\displaystyle 4}{\displaystyle 9}(x-5)$

I hope this helps!

4 0

3 years ago