I need help PLSS!! for math.Its due tomorow

Mathematics

1 answer:

PSYCHO15rus [73]3 years ago

8 0

Answer:

3 and 4

Step-by-step explanation:

those are the only numbers multiplied that equal 12

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VARVARA [1.3K]

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The correct answer to this problem is letter A.

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3 years ago

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Answer:

arithmetic sequence

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Step-by-step explanation:

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3 years ago

name the lengths of the sides of three rectangles with a perimeter of 12 units use only whole numbers

AysviL [449]

The perimeter of a rectangle is 2(w+l)
We can find the lengths by setting the equation equal to 12.
12=2(w+l)
12÷2=(2(w+l))÷2
6=w+l
6=1+5
6=2+4
6=3+3
These are the lengths of the sides of three rectangles with a perimeter of 12 units.
You're probably wondering why the third one has two of the same number, because that's usually how the lengths of sides of squares are, not rectangles.
Well, there's this wonderful thing about the rules of shapes.
<em>Squares ARE rectangles.
</em>Because they follow the rules for a rectangle, squares are also classified as rectangles.
So, the rectangle side lengths are as follows:
1 unit by 5 units
2 units by 4 units
3 units by 3 units
<em />

8 0

3 years ago

if it would take billy an hour to race over to his girlfriends house and two hours if he went 20 miles per hour slower how far a

mel-nik [20]

Recall your d = rt, distance = rate * time.

now, let's say she lives "d" miles away, and so if Billy goes say at "r" mph fast to her house, he gets there in 1hr.

now, if he goes 20 mph slower, namely " r - 20 " mph, he gets there in 2 hours, same "d" miles.

$\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
\textit{Billy}&d&r&1\\
\textit{slower Billy}&d&r-20&2
\end{array}
\\\\\\
\begin{cases}
d=r(1)\implies d=\boxed{r}\\
d=2(r-20)\\
----------\\
d=2\left( \boxed{d}-20 \right)
\end{cases}
\\\\\\
d=2d-40\implies 40=d$

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4 years ago

Evaluate log3^8, given log3^2 is equivalent to 0.631

elixir [45]

We will use the followin property of logarithms:

$log(a^b) = b log(a)$