Question

Length of a rectangle is 4x²+12x and the area of the rectangle is 24x⁴+72x³, what is the width of the rectangle?

Answer 1

Answer:

The width is $6x^2$

Step-by-step explanation:

The area of a rectangle is given as : $Area=l\times w$

This implies that: $w=\frac{Area}{l}$

We have that the length is $l=4x^2+12x$ and the area is $Area=24x^4+72x^3$

We substitute to get:

$w=\frac{24x^4+72x^3}{4x^2+12x}$

$\implies w=\frac{24x^2(x^2+3x)}{4(x^2+3x)}$

We cancel out the common factors to get:

$w=6x^2$