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3 years ago

Note: Type out the correct classification for each graph.

Mathematics

2 answers:

DedPeter [7]3 years ago

7 0

Answer:

1). Odd function

2).Odd function

3).Even funtion

Step-by-step explanation:

I just took the test...

saveliy_v [14]3 years ago

6 0

1) First is an odd function because f(-x)=-f(x)
3) 3d is an even function because f(-x)=f(x)
2) 2d looks like sin function and it is also odd.

You might be interested in

HELLLLP (will mark brainiest)

Zigmanuir [339]

Answer:

We put the value of the x in the formula

${4 \times }(6)^{2} - 7 \times 6 + 12$

f(6)=

$4 \times 36 - 7 \times 6 + 12 = 144 - 42 + 12 = 102 + 12 = 114$

Step-by-step explanation:

Than solve equation.

6 0

3 years ago

Read 2 more answers

50 pts!!!! Luciana's laptop has 3,000 pictures. The size of the pictures is skewed to the right, with a mean of 3.7MB and a stan

skelet666 [1.2K]

Answer:

Part A: No, you cannot.

Part B: 0.4491

Explanation:

Part A:

The mean of samples of symmetrical (bell shaped) distributions follow a normal distribution pattern.

Thus, for symmetrical distributions you can use the z-score tables to make calculations that permit calculate probabilities for particular values.

For skewed distributions, in general, the samples do not follow a normal distribution pattern, except that the samples are large.

Since a sample of 20 pictures is not large enough, the answer to this question is negative: you cannot accurately calculate the probability that the mean picture size is more than 3.8MB for an SRS (skewed right sample) of 20 pictures.

Part B.

For large samples, the Central Limit Theorem will let you work with samples from skewed distributions.

Although the distribution of a population is skewed, the Central Limit Theorem states that large samples follow a normal distribution shape.

It is accepted that samples of 30 data is large enough to use the Central Limit Theorem.

Hence, you can use the z-core tables for standard normal distributions to calculate the probabilities for a random sample of 60 pictures instead of 20.

The z-score is calculated with the formula:

z-score = (value - mean/ (standard deviation).

$z=(x-\mu )/\sigma$

Here, mean = 3.7MB, value = 3.8MB, and standard deviation = 0.78MB.

Thus:

$z=(3.7M-3.8MB)/(0.78MB)=-0.128$

Then, you must use the z-score table to find the probability that the z-score is greater than - 0.128.

There are tables that show the cumulative probability in the right end and tables that show the cumulative probability in the left end of a normal standard distribution .

The probability that a z-score is greater than -0.128 is taken directly from a table with the cumulative probability in the left end. It is 0.4491.

4 0

3 years ago

(a) How would you characterize the relationship between the hours spent on homework and the test scores? Explain.

cricket20 [7]

A) there is a linear relationship with the test scores go up with increasing hours spent on hw

b) y=8x+40 so at x=3h, y=test score= 8*3+40 = 64

c) 40 represents test score when u spend 0 hour on hw

5 0

2 years ago

Read 2 more answers

N is a positive integer

Murrr4er [49]

Part (1)

n is some positive integer. Let's say for now that n is even. So n = 2k, for some integer k

This means n-1 = 2k-1 is odd since subtracting 1 from an even number leads to an odd number.

Now multiply n with n-1 to get

n(n-1) = 2k(2k-1) = 2m

where m = k(2k-1) is an integer

The result 2m is even showing that n(n-1) is even

------------

Let's say that n is odd this time. That means n = 2k+1 for some integer k

And also n-1 = 2k+1-1 = 2k showing n-1 is even

Now multiply n and n-1

n(n-1) = (2k+1)(2k) = 2k(2k+1) = 2m

where m = k(2k+1) is an integer

We've shown that n(n-1) is even here as well.

------------

So overall, n(n-1) is even regardless if n is even or if n is odd.

Either n or n-1 will be even. If you multiply an even number with any number, the result will be even.

=======================================================

Part (2)

n is some positive integer

2n is always even since 2 is a factor of 2n

2n+1 is always odd because we're adding 1 to an even number. The sequence of integers goes even,odd,even,odd, etc and it does this forever.

-----------

Another way to see how 2n+1 is odd is to divide 2n+1 over 2 and you'll find that we get (2n+1)/2 = 2n/2+1/2 = n+0.5

The 0.5 at the end is not an integer, so there's no way that (2n+1)/2 is an integer; therefore 2n+1 is odd.

6 0

2 years ago

Determine the constant of varlation for the direct variation glven. Rvaries directly with S. When S is 16, R Is 80.

navik [9.2K]

Answer:

The constant of variation is 5.

Step-by-step explanation:

In direct variation, as y varies directly with x, the standard equation is

y = kx,

where k is the constant of variation.

In your case, we use R and S. R varies directly with S, so we have

R = kS

We know that when S = 16, R is 80, so we plug in those values and solve for k, the constant of variation.

R = kS

80 = k(16)

k = 80/16

k = 5

4 0

2 years ago