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Ratling [72]
3 years ago
9

(Squreroot x+2)(squreoot x-2)=0

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

\boxed{ \ x = 2  \ or \  x = -2 \ }

Step-by-step explanation:

I understand that you want to solve this equation

\sqrt{x+2}\sqrt{x-2}=0

<=>

\sqrt{(x+2)(x-2)}=0

<=>

(x+2)(x-2)=0

<=>

x = 2 or x = -2

hope this helps

if your question is (\sqrt{x}+2)(\sqrt{x}-2) = 0

then this is (\sqrt{x})^2-4 = 0\\ x = 4

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3 years ago
Making high-stakes insurance decisions. The Journal of Economic Psychology (Sept. 2008) published the results of a high-stakes e
Andrej [43]

Answer:

a. P(24)=0.00007

b. P(23)=0.00018

c. There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

Step-by-step explanation:

The probabilities of two events ("fire"and "theft") are compared to the probabilities of a certain number of days of rain during July.

The probabilities of "fire"and "theft" are around P=0.0001, and we need to calculate if the probability of exactly 23 and exactly 24 days of rain July have approximately the same probability.

Rain frequencies for the months of July and August were shown to follow a Poisson distribution with a mean of 10 days per month.

The parameter then is:

\lambda=10

The probability of k days of rain is:

P(k)=\frac{10^ke^{-10}}{k!}

For 24 days, the probability is:

P(24)=\frac{10^{24}e^{-10}}{24!}=\frac{1*10^{24}*4.54*10^{-5}}{6.20*10^{23}}  = 0.00007

The probability of 23 days of rain is 27% less than P=0.0001.

For 23 days of rain, the probability is:

P(23)=\frac{10^{23}e^{-10}}{23!}=\frac{1*10^{23}*4.54*10^{-5}}{2.59*10^{23}}  = 0.00018

The probability of 23 days of rain is 76% more than P=0.0001.

There is significant difference between the probability of the rainy days and the probabilities of fire and theft.

The probability of theft would be overestimated by 76% and the probability of fire would be subestimated by 27%.

8 0
3 years ago
The quotient of the sum of 2t and 2, twice the cube of s
natali 33 [55]

Answer: \frac{2t+2}{2s^3}

Step-by-step explanation:

Since you did not indicate what you need to do, I assume that you have to write an expression using the sentence given in the problem.

In order to solve this exercise, it is importat to remember the following information:

1. The quotient is the result of a division.

2. The sum is the result of an addition.

3. The word "twice" indicates a multiplicatio by 2.

4. The word "cube" indicates an exponent 3.

Then, keeping on mind the explained above and the data given in the exercise, you know that:

-The sum of 2t and 2 can be expressed as:

2t+2

- Twice the cube of s can be expressed in the following form:

2s^3

Therefore, you can dermine that "the quotient of the sum of  2t and 2 and twice the cube of s" is represented with the following expression:

\frac{2t+2}{2s^3}

O

8 0
3 years ago
Simplify 17-6•10/2+12
Agata [3.3K]
17-6 x 10/2+ 12

17-60/2+12

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3 0
3 years ago
Segment EG is an angle bisector of angle FGH. Noah wrote a proof to show that triangle HEG is congruent to triangle FEG. Noah's
tangare [24]

Answer:

Line 3 is incorrect; we don't know anything about the lengths of HG, FG, HE, and EF, so this line is not valid based on the given information.

Step-by-step explanation:

In the Noah's poof of the construction, segment EG would divide angle FGH into two equal parts, which makes line 2 to be valid. i.e <EGH ≅ <EGF. And it can also be observed that line 4 is a valid theorem in proving the congruent nature of triangles.

But line 3 is not valid because of the condition of the statement. Furthermore, segments FG, EG, HG, HE and FE may not be congruent. Thus, the condition of the statement in line 3 is incorrect.

8 0
3 years ago
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