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Ratling [72]
3 years ago
9

(Squreroot x+2)(squreoot x-2)=0

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

\boxed{ \ x = 2  \ or \  x = -2 \ }

Step-by-step explanation:

I understand that you want to solve this equation

\sqrt{x+2}\sqrt{x-2}=0

<=>

\sqrt{(x+2)(x-2)}=0

<=>

(x+2)(x-2)=0

<=>

x = 2 or x = -2

hope this helps

if your question is (\sqrt{x}+2)(\sqrt{x}-2) = 0

then this is (\sqrt{x})^2-4 = 0\\ x = 4

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Indefinite integral need help pleaseeeeeee
tatiyna
Integrate indefinite integral:
I=\int\frac{dx}{e^{2x}+3e^x+2}dx

Solution:
1. use substitution u=e^x 
=>
du=e^xdx
=>
dx=\frac{du}{e^x}
=>
dx=\frac{du}{u}
=>
I=\int\frac{du}{u(u^2+3u+2)}du
=\int\frac{du}{u(u+2)(u+1)}du
2. decompose into partial fractions
\frac{1}{u(u+2)(u+1)}
=\frac{A}{u}+\frac{B}{u+2}+\frac{C}{u+1}
where A=1/2, B=1/2, C=-1
=\frac{1}{2u}+\frac{1}{2(u+2)}-\frac{1}{u+1}
3. Substitute partial fractions and continue
I=\int\frac{du}{2u}+\int\frac{du}{2(u+2)}-\int\frac{du}{u+1}
=\frac{log(u)}{2}+\frac{log(u+2)}{2}-log(u+1)}
4. back-substitute u=e^x
=\frac{log(e^x)}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}
=\frac{x}{2}+\frac{log(e^x+2)}{2}-log(e^x+1)}

Note: log(x) stands for natural log, and NOT log10(x)

7 0
3 years ago
A local movie theater charges $12 for an adult ticket and $10 for a child's ticket. a group of eight people spent a total of $86
oksian1 [2.3K]
3 adults and 5 kids. 

You can get this by setting up the following system of equations.

x + y = 8 (number of people)
10x + 12y = 86 (cost)
7 0
3 years ago
12
vekshin1

Answer:

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Step-by-step explanation:

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4 years ago
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Answer:

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Step-by-step explanation:

4 0
3 years ago
Joe and kim split a pound of grab bag and gumdrops. how much did they each pay
juin [17]

$6.52 for the grab bag, divide that between two people and you get = $3.26

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$3.23/2 = $1.62

$1.62 + $3.26 = $4.88

each of them have to pay $4.88

5 0
3 years ago
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