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Ratling [72]
3 years ago
9

(Squreroot x+2)(squreoot x-2)=0

Mathematics
1 answer:
yuradex [85]3 years ago
7 0

Answer:

\boxed{ \ x = 2  \ or \  x = -2 \ }

Step-by-step explanation:

I understand that you want to solve this equation

\sqrt{x+2}\sqrt{x-2}=0

<=>

\sqrt{(x+2)(x-2)}=0

<=>

(x+2)(x-2)=0

<=>

x = 2 or x = -2

hope this helps

if your question is (\sqrt{x}+2)(\sqrt{x}-2) = 0

then this is (\sqrt{x})^2-4 = 0\\ x = 4

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