(8x4+64x3+3x-28)÷(x-8)
1 answer:
check the picture below.
recall that the division is done with the dividend and divisor sorted in descending order, notice the dividend has a jump from x³ to x, so the x² is missing, but is really there, but it has a coefficient of 0, as you see there in red, so we add any missing terms on either side.
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Consequently, t<span>he limit of
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so oblique asymptote is y=x.
I'm Japanese, if you find some mistakes in my English, please let me know.</span>
