(8x4+64x3+3x-28)÷(x-8)
1 answer:
check the picture below.
recall that the division is done with the dividend and divisor sorted in descending order, notice the dividend has a jump from x³ to x, so the x² is missing, but is really there, but it has a coefficient of 0, as you see there in red, so we add any missing terms on either side.
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Answer:
An equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is:
Step-by-step explanation:
The slope-intercept form of the line equation
where m is the slope and b is the y-intercept
Given the equation
Writing in the slope-intercept form of the line equation
comparing with the slope-intercept form of the line equation
y = mx+b
Thus, the slope of line = m = -6
We know that the parallel lines have the same slopes.
Thus, the slope of the parallel line is also -6.
As the line passes through the point (2,−5).
Thus, using the point-slope form of the line equation
where m is the slope and (x₁, x₂) is the point
substituting the values m = -6 and the point (2,−5)
subtract 5 from both sides
Therefore, an equation of the line that passes through the point(2,−5) and is parallel to the line 6x+y=6 is: