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barxatty [35]
3 years ago
7

Allison has five times as many baseball cards and football cards in all she has 120 baseball and football cards how many basebal

l cards does Alison have
Mathematics
1 answer:
ValentinkaMS [17]3 years ago
6 0
I think you do 120 divided by 5, but I could be wrong.
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X+2y=19 and x+y=13 in substitution methood​
densk [106]
X=7, y=6. that’s your answer!
3 0
3 years ago
Something divided by4 =9
coldgirl [10]
9 * 4 = 36  sooo 36 / 4 = 9

so the answer is 36 .

i hope this helps.
4 0
3 years ago
Read 2 more answers
Can anyone explain the basics of solving systems to linear equations?
Len [333]

Answer:

A system of linear equations is just a set of two or more linear equations. In two variables (x and y) , the graph of a system of two equations is a pair of lines in the plane. ... The lines intersect at infinitely many points.

Step-by-step explanation:

i hope this helped

3 0
3 years ago
Read 2 more answers
Solve the equation by graphing. If exact roots cannot be found, state the consecutive integers between which the roots are locat
zavuch27 [327]

Answer:

The equation contains exact roots at x = -4 and x = -1.

See attached image for the graph.

Step-by-step explanation:

We start by noticing that the expression on the left of the equal sign is a quadratic with leading term x^2, which means that its graph shows branches going up. Therefore:

1) if its vertex is ON the x axis, there would be one solution (root) to the equation.

2) if its vertex is below the x-axis, it is forced to cross it at two locations, giving then two real solutions (roots) to the equation.

3) if its vertex is above the x-axis, it will not have real solutions (roots) but only non-real ones.

So we proceed to examine the vertex's location, which is also a great way to decide on which set of points to use in order to plot its graph efficiently:

We recall that the x-position of the vertex for a quadratic function of the form f(x)=ax^2+bx+c is given by the expression: x_v=\frac{-b}{2a}

Since in our case a=1 and b=5, we get that the x-position of the vertex is: x_v=\frac{-b}{2a} \\x_v=\frac{-5}{2(1)}\\x_v=-\frac{5}{2}

Now we can find the y-value of the vertex by evaluating this quadratic expression for x = -5/2:

y_v=f(-\frac{5}{2})\\y_v=(-\frac{5}{2} )^2+5(-\frac{5}{2} )+4\\y_v=\frac{25}{4} -\frac{25}{2} +4\\\\y_v=\frac{25}{4} -\frac{50}{4}+\frac{16}{4} \\y_v=-\frac{9}{4}

This is a negative value, which points us to the case in which there must be two real solutions to the equation (two x-axis crossings of the parabola's branches).

We can now continue plotting different parabola's points, by selecting x-values to the right and to the left of the x_v=-\frac{5}{2}. Like for example x = -2 and x = -1 (moving towards the right) , and x = -3 and x = -4 (moving towards the left.

When evaluating the function at these points, we notice that two of them render zero (which indicates they are the actual roots of the equation):

f(-1) = (-1)^2+5(-1)+4= 1-5+4 = 0\\f(-4)=(-4)^2+5(-4)_4=16-20+4=0

The actual graph we can complete with this info is shown in the image attached, where the actual roots (x-axis crossings) are pictured in red.

Then, the two roots are: x = -1 and x = -4.

5 0
3 years ago
Which equation has no solution?
konstantin123 [22]

Answer:

B) 4x-5-3x=x+5 has no solution.

Step-by-step explanation:

A) 4x+4=4-4x

4x-(-4x)+4=4

4x+4x+4=4

8x+4=4

8x=4-4

8x=0

x=0/8

x=0

------------------

B) 4x-5-3x=x+5

4x-3x-5=x+5

x-5=x+5

x-x-5=5

-5=5

no solution.

------------------------

C) 4x+15-9x=5x+15

4x-9x+15=5x+15

-5x+15=5x+15

-5x-5x+15=15

-10x+15=15

-10x=15-15

-10x=0

x=0/-10

x=0

------------------------

D) 4x+2-x=4+3x-2

3x+2=3x+4-2

3x+2=3x+2

infinitely many solutions.

8 0
2 years ago
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