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insens350 [35]
3 years ago
10

Rachna purchases a plant that is 6 inches tall. Every week the plant grows an additional 0.6 inches. Rachna draws a graph of the

function that models the plant’s growth. The x-axis is labeled Weeks and the y-axis is labeled Height in inches. What is the slope of the function?
Mathematics
1 answer:
aleksklad [387]3 years ago
5 0

Answer:

0.6

Step-by-step explanation:

Slope is the change in y divided by change in x.

x is weeks

y is height

We know plant grows 0.6 inches every week. This means per 1 week [change in x], the plant grows 0.6 inches [change in y]

Slope = 0.6/1 = 0.6

0.6 is the slope of the function

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Oduvanchick [21]

Answer:

The answer is 35

Step-by-step explanation:

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3 years ago
Cesar can hike at 3 1/3 miles in 2 hours. Bella can hike 1/3 mile in 1/4 hour.
Svetlanka [38]

Answer:

Cesar goes 1 2\3 miles in an hour

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
A. Solve the differential equation <img src="https://tex.z-dn.net/?f=y%27%3D2x%20%5Csqrt%7B1-y%5E2%7D%20" id="TexFormula1" title
kirill [66]
y' = \frac{dy}{dx}

seperable differential equations will have the form
\frac{dy}{dx} = F(x) G(y)

what you do from here is isolate all the y terms on one side and all the X terms on the other
\frac{dy}{G(y)} = F(x) dx
just divided G(y) to both sides and multiply dx to both sides

then integrate both sides
\int \frac{1}{G(y)} dy = \int F(x) dx&#10;&#10;

once you integrate, you will have a constant. use the initial value condition to solve for the constant, then try to isolate x or y if the question asks for it


In your problem,
G(y) = \sqrt{1-y^2}&#10;&#10;F(x) = 2x

so all you need to integrate is
\int \frac{1}{\sqrt{1-y^2}} dy = \int 2x dx
5 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!<br><br> Graph g(x) = 3x^2 - 12x - 3
Paul [167]

Answer: Vertex = (2, -15)  2nd point = (0, -3)

<u>Step-by-step explanation:</u>

g(x) = 3x² - 12x - 3

      = 3(x² - 4x - 1)

          a=1   b=-4  c=-1

Find the x-value of the vertex by using the formula for the axis of symmetry: x = \dfrac{-b}{2a}

x = \dfrac{-(-4)}{2(1)}

      = \dfrac{4}{2}

         = 2

Find the y-value of the vertex by plugging the x-value (above) into the given equation: g(x) = 3x² - 12x - 3

g(2) = 3(2)² - 12(2) - 3

       = 12  - 24 - 3

       = -15

So, the vertex is (2, -15)  ←  PLOT THIS COORDINATE

Now, choose a different x-value.  Plug it into the equation and solve for y. <em>I chose x = 0</em>

g(0) = 3(0)² - 12(0) - 3

       = 0  - 0 - 3

       = -3

So, an additional point is (0, -3)  ←  PLOT THIS COORDINATE


5 0
3 years ago
Determine if the given differential equation is exact (e^2y-y cos xy)dx+(2xe^2 y-cos xy+2y)dy=0
rewona [7]
\dfrac\partial{\partial y}\left[e^{2y}-y\cos xy\right]=2e^{2y}-\cos xy+xy\sin xy

\dfrac\partial{\partial x}\left[2xe^{2y}-y\cos xy+2y\right]=2e^{2y}+y\sin xy

The partial derivatives are not equal, so the equation is not exact.
7 0
3 years ago
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