Answer:
The probability that a part was manufactured on machine A is 0.3
Step-by-step explanation:
Consider the provided information.
It is given that Half of a set of parts are manufactured by machine A and half by machine B.
P(A)=0.5
Let d represents the probability that part is defective.
Ten percent of all the parts are defective.
P(d) = 0.10
Six percent of the parts manufactured on machine A are defective.
P(d|A)=0.06
Now we need to find the probability that a part was manufactured on machine A, and given that the part is defective
:



Hence, the probability that a part was manufactured on machine A is 0.3
Number of shares
1050/10=105
After one year share value
10×(1+0.13)=11.3
After the second year share value
11.3×(1−0.05)=10.735
Total
10.735×105=1,127.175
Answer:
4x+2
Step-by-step explanation:
2(2x+1)
4x +2
you distribute the the 2