As the ball falls, the velocity of the ball increases with increase in distance
<h3>Velocity and Motion</h3>
Given Data
It should be noted that when an object falls, it velocity increases from zero to the maximum just before it hits the ground from the initial point of lunch.
Note: For a projectile the ball might reach a zero velocity at maximum height
Learn more about velocity here:
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Answer:
-3x - 5
Step-by-step explanation:
Answer:
Point B is (1, 2)
Step-by-step explanation:
Let us revise the rule of the translations
- If the point (x, y) translated horizontally to the right by h units then its image is (x + h, y) ⇒ T (x, y) → (x + h, y)
- If the point (x, y) translated horizontally to the left by h units then its image is (x - h, y) ⇒ T (x, y) → (x - h, y)
- If the point (x, y) translated vertically up by k units then its image is (x, y + k)→ (x + h, y) ⇒ T (x, y) → (x, y + k)
- If the point (x, y) translated vertically down by k units then its image is (x, y - k) ⇒ T (x, y) → (x, y - k)
∵ Point A = (-2, 0)
∵ T (3, 2) → A = B
→ By using the 1st and 3rd rules above, A is translated 3 units right and 2
units up to get B
∴ T (x, y) → (x + 3, y + 2)
∵ A = (x, y)
∵ x = -2 and y = 0
∴ B = (-2 + 3, 0 + 2)
∴ B = (1, 2)
∴ Point B is (1, 2)
Answer:
= 1.80909 × 104
(scientific notation) (MOST COMMON)
Step-by-step explanation:
= 1.80909 × 104
(scientific notation)
= 1.80909e4
(scientific e notation)
= 18.0909 × 103
(engineering notation)
(thousand; prefix kilo- (k))
= 18090.9
(real number)
Please mark this as brainliest, it would help a lot
Answer: brand C
Step-by-step explanation:
i just took the quiz
