The interquatile range is adding t
Answer:
Age of son = 6 years
Age of man = 5×6 = 30 years
Step-by-step explanation:
<u>GIVEN :-</u>
- A man is 5 times as old as his son. (In Present)
- 4 years ago , the man was 13 times as old as his son
<u>TO FIND :-</u>
- The present ages of the man & his son.
<u>SOLUTION :-</u>
Let the present age of son be 'x'.
⇒ Present age of man = 5x
4 years ago ,
Age of son = (Present age of son) - 4 = x - 4
Age of man = (Present age of man) - 4 = 5x - 4
The man was thirteen times as old as his son. So,

Now , solve the equation.
- Open the brackets in R.H.S.

- Take 5x to R.H.S. and -52 to L.H.S. Also , take care of their signs because they are getting displaced from L.H.S. to R.H.S. or vice-versa.


- Divide both the sides by 8


<u>CONCLUSION :-</u>
Age of son = 6 years
Age of man = 5×6 = 30 years
-9+3x
2(9-3x)/-2
-(9-3x)
-9+3x
Brainliest?
Answer:
C
Step-by-step explanation:
I took the test
Answer: y = -6x + 2
m = y_2 - y_1
/ x_2 - x_1
-10 - 8
/ 2 - (-1)
= -18/3 = -6
m (slope) = -6
y = mx + b
y = -6x +b
Find b using (-1,8)
y = -6x +b
8 = -6(-1) + b
8 = 6 + b
-6 -6
2 = b
Final answer: y = -6x + 2
To check using one of the points: (-1,8) or (2,-10)
y = -6x + 2
-10 = -6(2) + 2
-10 = -12 + 2
-10 = -10
This is a true statement.