Question

Need some help thanks, bye.

Answer 1

Answer:

Option C

Step-by-step explanation:

We solve the system of equations by using the Elimination method as follows,

$2x-5y=-5\\x+2y=11$

We multiply the second equation with -2 and then add both the equations  to eliminate the variable x

$-2(x+2y=11) \\-2x-4y=-22$

so now,

$2x-5y=-5\\-2x-4y=-22\\2x+(-2x)-5y+(-4y)=-5+(-22)\\2x-2x-5y-4y=-5-22\\0-9y=-27\\-9y=-27\\y=-27/-9\\y=3$

we found the value of y to be y = 3 now we insert this value in any equation of the system either it be the first or the second to calculate the value of x so here goes,

$x+2y=11\\x+2(3)=11\\x+6=11\\x=11-6\\x=5$

so the solution to the system of equations is (5 , 3) not (10 , 5) which is given in the question even though the ordered pair (10 , 5) satisfies the first equation it is not the solution to the system because in the system it has two equations instead of one so (10 , 5) holds true for the first equation not for the second so Option C is your best answer because it atleast makes one of the equations false.