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3 years ago

Need some help thanks, bye.

Mathematics

1 answer:

vovangra [49]3 years ago

6 0

Answer:

Option C

Step-by-step explanation:

We solve the system of equations by using the Elimination method as follows,

$2x-5y=-5\\x+2y=11\\$

We multiply the second equation with -2 and then add both the equations to eliminate the variable x

$-2(x+2y=11) \\-2x-4y=-22$

so now,

$2x-5y=-5\\-2x-4y=-22\\2x+(-2x)-5y+(-4y)=-5+(-22)\\2x-2x-5y-4y=-5-22\\0-9y=-27\\-9y=-27\\y=-27/-9\\y=3$

we found the value of y to be y = 3 now we insert this value in any equation of the system either it be the first or the second to calculate the value of x so here goes,

$x+2y=11\\x+2(3)=11\\x+6=11\\x=11-6\\x=5\\$

so the solution to the system of equations is (5 , 3) not (10 , 5) which is given in the question even though the ordered pair (10 , 5) satisfies the first equation it is not the solution to the system because in the system it has two equations instead of one so (10 , 5) holds true for the first equation not for the second so Option C is your best answer because it atleast makes one of the equations false.

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Question 14 of 25What is the complete factorization of the polynomial below?x³+x² + 4x+4O A. (x-1)(x+2)(x+2)B. (x + 1)(x + 2)(x

mote1985 [20]

GIVEN:

We are given the following polynomial;

$x^3+x^2+4x+4$

Required;

We are required to factorize this polynomial completely.

Step-by-step explanation;

To factorize this polynomial, we start by grouping;

$(x^3+x^2)+(4x+4)$

We now take the common factor in each group;

$\begin{gathered} x^2(x+1)+4(x+1) \\ \\ (x^2+4)(x+1) \end{gathered}$

Next, we factorize the first parenthesis. To do this we set the equation equal to zero and solve for x as follows;

$\begin{gathered} x^2+4=0 \\ \\ Subtract\text{ }4\text{ }from\text{ }both\text{ }sides: \\ \\ x^2=-4 \\ \\ Take\text{ }the\text{ }square\text{ }root\text{ }of\text{ }both\text{ }sides: \\ \\ x=\pm\sqrt{-4} \\ \\ x=(\pm\sqrt{-1}\times\sqrt{4}) \\ \\ x=\pm2i \end{gathered}$

Therefore, the factors of the other parenthesis are;

$(x+2i)(x-2i)$

Therefore, the complete factorization of the polynomial is;

ANSWER:

$(x+1)(x+2i)(x-2i)$

Option C is the correct answer.

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1 year ago

A right rectangular prism has edges of 8 feet, 4 feet, and 1/2 foot. How many cubes with side lengths of 1/2 foot would be neede

Ksenya-84 [330]

Answer:

Step-by-step explanation:

From the question we are told that

Edges of 8 feet, 4 feet, and 1/2 foot

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$V_p=8*4*0.5$

$V_p=16$

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Therefore total number of cubes is given as

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3 years ago

In sporting tournaments, teams are eliminated after they lose. The number of teams in the

tresset_1 [31]

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3 years ago

Dean needs $150 for a miming class. He already has $85 and he can earn the rest by working 13 hours at his job. If h represents

AnnyKZ [126]

Answer:

h=$65/13

Step-by-step explanation:

So he has $85

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And in every 13h he produces the $65

So to find his hourly earning is h=$65/13

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3 years ago

Stevie and Michael share their profit in a ratio 3:5. Stevie gets £120 more than Michael. How much profit did they make altogeth

Airida [17]

Answer:

£480

Step-by-step explanation:

we can multiply both terms of ratio with same number without changing the ratio.

Example

a:b = ax: bx (here we have multiplied both terms with x)\

Given

Stevie and Michael share their profit in a ratio 3:5

Let the profit for Stevie and Michael be 3x and 5x

Given Stevie gets £120 more than Michael

Profit for Steve = 120 + profit for Michael

3x = 120 + 5x

3x-5x = 120

=> -2x = 120

=> x= -120/2 = -60

As we see profit is negative , hence it cannot be solution.

It can be solved if Stevie and Michael share their profit in a ratio 5:3

(note: in ratio , bigger number should have bigger term in ratio)

Let the profit for Stevie and Michael be 3x and 5x

Given Stevie gets £120 more than Michael

Profit for Steve = 120 + profit for Michael

5x = 120 + 3x

5x-xx = 120

=> 2x = 120

=> x= x120/2 = 60

Profit for stevei = 5x =5*60 = 300

Profit for Michael = 3x = 3*60 = 180

Total profit for them together = 300 + 180 = 480 Answer.

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3 years ago