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eduard
3 years ago
6

Ella bought some keychains if she paid $24 for the keychains and each one cost the same hole dollar amount how many couldshe hav

e bought?
Mathematics
2 answers:
worty [1.4K]3 years ago
8 0
The numbers divisible by 24 are 1,2,3,4,6,8,12,24


1 and 24
2 and 12
3 and 8
4 and 6 a
& vice versa

so the least she could have bought would be 1 for $24
and the most she could have bought would be 24 for $1
Afina-wow [57]3 years ago
7 0
She would have 24 because she only has one dollar bills
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What is the solution of the inequality 7(x + 4) < 2(x–5) + 3(x + 9)?
emmasim [6.3K]

Answer:

x< -8.125

Step-by-step explanation:

7(x+4) < 2(x-5) -3(x+9)

distribute 7, 2, -3 to the parentheses to the right

7x+28<2x-10-3x-27

add like terms

7x+28<x-37

add x to 7x and subtract -28 to -37

8x<-65

divide both sides by 8

x<-8.125 or (-65/8)

5 0
4 years ago
a plant is 20 inch tall. if the plant grows 2h inches each week for the next 4 weeks, and h inches for each of the 2 weeks after
devlian [24]
Is it 116? if i didnt add that up wrong thats the answer

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3 years ago
What is the mean average deviation of 5, 6, 6, 7, 9, 10, 10, 11.​
Bingel [31]

Answer:

7.8 rounding up to 8

Step-by-step explanation:

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3 years ago
Write the partial fraction decomposition fro the ration expression below
zlopas [31]
\dfrac{5x-2}{(x-1)^2}=\dfrac a{x-1}+\dfrac b{(x-1)^2}
5x-2=a(x-1)+b

Since 5x-2=5x-5+3=5(x-1)+3, it follows that a=5 and b=3, so

\dfrac{5x-2}{(x-1)^2}=\dfrac5{x-1}+\dfrac3{(x-1)^2}

\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac{x^3+x+x+2}{x^2(x^2+1)}=\dfrac ax+\dfrac b{x^2}+\dfrac{cx+d}{x^2+1}
x^3+x^2+x+2=ax(x^2+1)+b(x^2+1)+(cx+d)x^2
x^3+x^2+x+2=(a+c)x^3+(b+d)x^2+ax+b

When x=0, you find that b=2. It's also clear that a=1. So the remaining constants must be 1+c=1\implies c=0 and 2+d=1\implies d=-1, and so you get

\dfrac{x^3+x^2+x+2}{x^4+x^2}=\dfrac1x+\dfrac2{x^2}-\dfrac1{x^2+1}
6 0
4 years ago
Can someone help me with these problems? Please!
masya89 [10]

Step-by-step explanation:

2) Slope can be written as rise over run:

  • rise: add to the y-value
  • run: add to the x-value

a) Slope=-1\ over\ 1\quad \rightarrow \quad (11 + 1, -8 - 1)\implies (12, -9)\\b) Slope=7\ over\ 2\quad \rightarrow \quad (2+2,2+7)\implies (4, 9)\\c) Slope=9\ over\ 4\quad \rightarrow \quad (-5+4,-2+9)\implies (-1, 7)

3) Slope formula is: \dfrac{y_2-y_1}{x_2-x_1}

slope=\dfrac{15-3}{5-1}=\dfrac{12}{4}=\boxed{3}

4) Average rate of change is the slope of the given interval:

a) when x = 0, y = 0 and when x = 1, y = -3

   Slope=\dfrac{-3-0}{1-0}=\dfrac{-3}{1}=-3

b) when x = -2, y = 0 and when x = -1, y = 3

   Slope=\dfrac{3-0}{-1+2}=\dfrac{3}{1}=3

c) when x = 0, y = 0 and when x = 2, y = 0

   Slope=\dfrac{0-0}{2-0}=\dfrac{0}{2}=0

3 0
4 years ago
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