The first part says the sum of the squares of two consecutive integers or in other words (x)(x)+(x+1)(x+1) so we can cross out A because 2 and 3 are prime numbers (no factors) we can cross out all the others because the square root of 52 is not an integer so any equation with 52 in it does not satisfy the requirement. so none of them are corect. additionally, some of the equations are obviously false such as 52+62=61
Answer:
-1 3/4 =x
Step-by-step explanation:
-3 1/2= 1/2x+1/2x+x
Combine like terms
-3 1/2 = 2x
Change to an improper fraction
- ( 2*3+1)/2 = 2x
-7/2 = 2x
Multiply each side by 1/2
-7/2 *1/2 = 2x* 1/2
-7/4 = x
Changing to a mixed number
-4/4 -3/4 =x
-1 3/4 =x
For 18% it will take 2 years to pay
For 3 years payment will be $36.50
For 14% it will take 1.9 years or 23 months
Answer:
x = 4
Step-by-step explanation:
6x - 8 = 4x
-6x -6x
-8 = -2x
-----------
-2
x = 4
LHS ⇒ RHS:
Identities:
[1] cos(2A) = 2cos²(A) - 1 = 1 - 2sin²(A)
[2] sin(2A) = 2sin(A)cos(A)
[3] sin(A + B) = sin(A)cos(B) + cos(A)sin(B)
[4] cos(A + B) = cos(A)cos(B) - sin(A)sin(B)
cos(x) - cos(x + 2Θ)
= cos(x) - (cos(x)cos(2Θ) - sin(x)sin(2Θ)) [4]
= cos(x) - cos(x)(1 - 2sin²(Θ)) + sin(x)(2sin(Θ)cos(Θ)) [1] [2]
= cos(x) - cos(x) + 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin²(Θ)cos(x) + 2sin(Θ)sin(x)cos(Θ)
= 2sin(Θ)(sin(Θ)cos(x) + sin(x)cos(Θ))
= 2sin(Θ)sin(x + Θ)