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3 years ago

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Imagine you have to deliver a speech on independence day prepare a speech

1 answer:

ELEN [110]3 years ago

3 0

Answer:Independence Day Speech

I wish you a great morning full of patriotism. Respected Chairman, Director, Principal, teachers and my dear friends, I congratulate you on the celebrations 71st Independence Day. Let’s remember on this day our great freedom fighters and leaders who sacrificed their everything to make our motherland free. Let’s bow our heads to Bhagat Singh, Rajguru, Sukhdev, Subhash Chader Bose, Mahatma Gandhi, and many more whose names we don’t know who lived and died for India.

Let us also take a pledge on this great day that we will carry on the struggle till we make our motherland free of all the ills of corruption, backwardness, narrow-mindedness, poverty, misuse of resources, and communalism. Let’s take a pledge we will be responsible citizens of our great country and serve it with our grand deeds and actions. Jai Hind.

please mark as brainliest

Step-by-step explanation:

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Step-by-step explanation:

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What is 0.8%of $5,700?

EastWind [94]

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Step-by-step explanation:

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Step-by-step explanation:

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butalik [34]

Point slope form is :

8+12 = m(9-4)

8+12= 9m -4m

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3 years ago

Please answer correctly !!!!!!! Will mark brainliest !!!!!!!!!!!!

LUCKY_DIMON [66]

Answer:

$=8\sqrt{15}b^{\frac{7}{2}}$

Step-by-step explanation:

$\sqrt{24b^3}\sqrt{40b^2}\sqrt{b^2}$

$=\sqrt{40}\sqrt{b^2}\sqrt{b^2}\sqrt{24b^3}$

$=\sqrt{40}b^2\sqrt{24b^3}$

$\sqrt{24b^3}$

$=\sqrt{24}\sqrt{b^3}$

$=\sqrt{24}b^{\frac{3}{2}}$

$=\sqrt{24}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3\cdot \:3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=\sqrt{2^3}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$\sqrt{2^3}$

$=2^{3\cdot \frac{1}{2}$

$=2^{3\cdot \frac{1}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{40}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3\cdot \:5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\sqrt{2^3}\sqrt{5}b^2$

$=2^{\frac{3}{2}}\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}b^{\frac{3}{2}}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^2$

$=\sqrt{3}\cdot \:2^{\frac{3}{2}+\frac{3}{2}}\sqrt{5}b^{\frac{3}{2}+2}$

$2^{\frac{3}{2}+\frac{3}{2}}$

$=2^3$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{3}{2}+2}$

$b^{\frac{3}{2}+2}$

$=b^{\frac{7}{2}}$

$=2^3\sqrt{3}\sqrt{5}b^{\frac{7}{2}}$

$=2^3\sqrt{3\cdot \:5}b^{\frac{7}{2}}$

$=8\sqrt{15}b^{\frac{7}{2}}$

4 0

3 years ago