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nevsk [136]
3 years ago
10

(2m - 5m^3 ) - (5m + 3m^3- 7m^4 ) + (8 - 3m^3- 5m^4+ 4m)

Mathematics
2 answers:
Tresset [83]3 years ago
6 0

Answer:

2m^4 - 11m³ + m + 8

Step-by-step explanation:

(2m - 5m³) - (5m + 3m³ - 7m^4) + (8 - 3m³ - 5m^4 + 4m)

2m - 5m³ - 5m - 3m³ + 7m^4 + 8 - 3m³ - 5m^4 + 4m

7m^4 - 5m^4 - 5m³ - 3m³ - 3m³ + 2m - 5m + 4m + 8

2m^4 - 11m³ + m + 8

sweet [91]3 years ago
4 0

Answer:

8 + m - 11m^3 + 2m^4

Step-by-step explanation:

Add and subtract like terms:

8 + (2m - 5m +4m) + (-5m^3 - 3m^3 - 3m^3) + (7m^4 - 5m^4) =

8 + m - 11m^3 + 2m^4

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PLS HELP I HAVE ALOT TO ANSWER AND TY IF YOU DO!!
Assoli18 [71]

Answer:

B: supplementary because they add up to 180 degrees

4 0
3 years ago
Tell whether the angles are complementary or supplementary. Then find the value of x
luda_lava [24]

Answer:

Complementary, x=78

Step-by-step explanation:

90= (x-8)+20

complementary angles add up to 90 degrees.

3 0
3 years ago
Read 2 more answers
Consider a single spin on the spinner shown below. A circle is split into sections 1, 2, 4, and 3. A spinner is pointing at numb
vladimir2022 [97]

Answer:

The answer is "Options A, B, and E represent mutually exclusive events".

Step-by-step explanation:

Two occurrences that can happen immediately called mutually incompatible. Let's now glance at our options and figure out where the statements are mutually incompatible events.

In Option A: You could see that landing on an unwanted portion and arriving on 2 are events that are locally incompatible, even as undesirable portion contains 3 and 4, and 2 were shaded.

In Option B: Arriving on a shaded part and falling on 3 are also mutually incompatible because there are 3 on a windows azure.

In Option C: A darkened portion and an increasing amount can land while 2 would be an even number as well as on the shaded portion. That number is very much the same.

In Option D: At the same time as 4 is greater than 3 and it is situated upon an undistressed section, landing and attracting a number larger than 3 can happen.

In Option E: Landing on a shaded part and landing on even a shaded part is an excluding event, since shaders may either be shaded or unlit.

3 0
3 years ago
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Could use some help pls.
Murrr4er [49]

Answer:

9 cans of soup and the 4 frozen dinners were purchased

Step-by-step explanation:

Let x represent the number of cans of soup purchased.

Let y represent the number of frozen dinners purchased.

Lincoln purchased a total of 13 cans of soup and frozen dinners. This means that

x + y = 13

Each can of soup has 250 mg of sodium and each frozen dinner has 550 mg of sodium. The 13 cans of soup and frozen dinners which he purchased collectively contain 4450 mg of sodium. This means that

250x + 550y = 4450 - - - - - - - - -1

Substituting x = 13 - y into equation 1, it becomes

250(13 - y) + 550y = 4450

3250 - 250y + 550y = 4450

- 250y + 550y = 4450 - 3250

300y = 1200

y = 1200/300

y = 4

Substituting y = 4 into x = 13 - y, it becomes

x = 13 - 4 = 9

7 0
3 years ago
3. Are these ratios equivalent? 35:28 and 10:8 *
attashe74 [19]

Reduce each ratio to its minimum expression to find if they are equal.

35:28

\begin{gathered} \frac{35}{28}=\frac{7\cdot5}{7\cdot4} \\ =\frac{5}{4} \end{gathered}

10:8

\begin{gathered} \frac{10}{8}=\frac{2\cdot5}{2\cdot4} \\ =\frac{5}{4} \end{gathered}

Since both ratios reduce to 5:4, they are equivalent.

Another way to check a:b is equivalent to c:d, is that a*d = b*c

In this case, this will be true if 35 times 8 is equal to 10 times 28:

\begin{gathered} 35\cdot8=280 \\ 10\cdot28=280 \end{gathered}

Since both products are equal, then the ratios are equivalent.

4 0
1 year ago
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