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ratelena [41]
3 years ago
9

What number (n) must be inserted into the number 3n,85n for it to be divisible by 6?

Mathematics
1 answer:
Dima020 [189]3 years ago
5 0
<span>N = number that must be inserted in the given numbers to be divisible by 6
=> 3n
=> 85n
Now, let’s find a best number that will multiplied with both given number and is divisible with 6.
=> 85n / 6
=> 85(6) / 6
=> 510 / 6
=>n =  6
now, let’s try to 3
=> 3(6) / 6
=> 18 / 6
=> 3
Thus, the value of N is 6 because it is divisible by 6 when multiplied to the given number.

</span>



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You move down 6 units. You end at (10, 4). Where did you start?
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9514 1404 393

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  14,201 years

Step-by-step explanation:

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  A = P·e^(rt) . . . . . continuous compounding at rate r for t years

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We went the amounts to be equal:

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<em>Additional comment</em>

The investment value at that time will be about $5.269·10^434. (That's a larger number than <em>anything</em> countable in the known universe, including energy quanta.)

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