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otez555 [7]
2 years ago
7

0.32 with the 2 repeating as a fraction

Mathematics
1 answer:
pashok25 [27]2 years ago
3 0

Answer:

29/90

Step-by-step explanation:

Use the formula:

((DN x F) - NRP)/D

DN = Decimal Number

F = 10 if one repeating number, 100 if two repeating numbers, 1000 if three repeating numbers, etc.

NRP = Non-repeating part of decimal number.

D = 9 if one repeating number, 99 if two repeating numbers, 999 if three repeating numbers, etc.

((0.32 x 10) - 0.3)/9

= 2.9/9  = 29/90

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8/3 x 9/7 or 8/3 x 9/4<br> Which is greater? How do you know?
Vinvika [58]

Well, let's multiply them!

8/3 * 9/7 = 72/21

8/3 x 9/4 = 72/12.

We know the one with the smallest denominator is larger if the numerator is the same. So that means

72/12 is larger.

5 0
3 years ago
................................................................................................................................
Alborosie

Answer:

its 65. bcuz you add it all together

Step-by-step explanation:

6 0
3 years ago
Aiden invested $43,000 in an account paying an interest rate of 9 % compounded
Shkiper50 [21]

Answer:

4.8 i think

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5 0
3 years ago
Find the orthocenter of the triangle with the given vertices: L(2, 2), M(-4, 2), N(-2, 6) a (-2, 4) b (3, -5) c (2, -4) d (-3, 5
Norma-Jean [14]

9514 1404 393

Answer:

  (a)  (-2, 4)

Step-by-step explanation:

The orthocenter is the point of concurrence of the altitudes of the triangle.

A plot of the triangle vertices shows the triangle to be acute. That means the orthocenter is inside. This eliminates choices B, C, D, which are all points outside the triangle.

__

Conveniently, side LM is horizontal. This means the orthocenter will have the x-coordinate of the vertical line through N, which is -2. Only one answer choice has an x-coordinate of -2:

  a (-2, 4)

8 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!<br><br> Subract and simplify.
pantera1 [17]

Answer: C

<u>Step-by-step explanation:</u>

  \dfrac{x+1}{x-5} - \dfrac{x-2}{x+3}

= \dfrac{x+1}{x-5}(\dfrac{x+3}{x+3}) - \dfrac{x-2}{x+3}(\dfrac{x-5}{x-5})

= \dfrac{x^{2}+4x+3}{(x-5)(x+3)} - \dfrac{x^{2}-7x+10}{(x-5)(x+3)}

= \dfrac{x^{2}+4x+3-(x^{2}-7x+10)}{(x-5)(x+3)}

= \dfrac{11x-7}{(x-5)(x+3)}

5 0
3 years ago
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