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2 years ago

7

0.32 with the 2 repeating as a fraction

1 answer:

pashok25 [27]2 years ago

3 0

Answer:

29/90

Step-by-step explanation:

Use the formula:

((DN x F) - NRP)/D

DN = Decimal Number

F = 10 if one repeating number, 100 if two repeating numbers, 1000 if three repeating numbers, etc.

NRP = Non-repeating part of decimal number.

D = 9 if one repeating number, 99 if two repeating numbers, 999 if three repeating numbers, etc.

((0.32 x 10) - 0.3)/9

= 2.9/9 = 29/90

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Which statement is true? A.27/19<11/30 B.17/31>19/14 C.16/26>30/31 D.35/30<22/12

Mrac [35]

A. $\frac{27}{19}$

To find greater than or smaller than relation, we multiply the terms like (numerator of L.H.S with denominator of R.H.S and put the value on the left side. Then multiply the denominator of L.H.S with numerator of R.H.S and put the value on right side. Now compare the digits.)

So, solving A, we get 810<209 ... This is false

B. $\frac{17}{31}>\frac{19}{14}$

= 238>589 ..... This is false

C. $\frac{16}{26}>\frac{30}{31}$

= 496>780 .... This is false

D. $\frac{35}{30}$

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3 years ago

What is the simplified value of the exponential expression 16 Superscript one-fourth?

pochemuha

<u>Answer: </u>

The value of the exponential expression $16^{\frac{1}{4}}$ is 2

<u>Solution:</u>

16 superscript one-fourth= $16^{\frac{1}{4}}$

As per the problem,

We have to find the value of $16^{\frac{1}{4}}$

16 in terms of 2 can be written as $2\times2\times2\times2$

= $(2 \times 2 \times 2 \times 2)^{\frac{1}{4}}$

= $\left(2^{4}\right)^{\frac{1}{4}}$

As per the exponential rule, $a^{(m)^{n}}=a^{m \times n}$

= $2^{4 \times \frac{1}{4}}$

Here, $4\times\frac{1}{4}=1$

= $2^{1}$

= 2

Hence, the value is 2.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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