Let the number be x,
(1/2)x=1+(1/3)x
Solving for x,
(1/2)x-(1/3)x=1+(1/3)x-(1/3)x
(1/2)x-(1/3)x=1
(1*3/6)x-(1*2/6)x=1
(3/6)x-(2/6)x=1
(1/6)x=1
6*(1/6)x=6*1
Therefore, x=6

7 0

3 years ago

Read 2 more answers

This is a repost since i forgot the photo on the last one help plz

tatuchka [14]

Answer:

Sorry but I don't know

Step-by-step explanation:

4 0

3 years ago

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Let AB = 24, AC = 10 and BC = 26.

nata0808 [166]

Answer:

a) 24

b) 10

c) 12/13

d) 5/13

e) 12/5

Step-by-step explanation:

a) We can see that the leg opposite <C is AB, and we are given AB = 24

b) We can see the leg adjacent to <C is AC, and we are given that AC = 10

c) The trig function sine is equal to

$\frac{opposite}{hypotenuse}$

The opposite, AB, is 24, and the hypotenuse, BC, is 26. We can plug those numbers in:

$sin(c) = \frac{24}{26} = \frac{12}{13}$

d)The trig function cosine is equal to

$\frac{adjacent}{hypotenuse}$

The adjacent, AC, is 10, and the hypotenuse, BC, is 26. We can plug those numbers in:

$cos(c) = \frac{10}{26} = \frac{5}{13}$

d)The trig function tangent is equal to

$\frac{opposite}{adjacent}$

The opposite, AB, is 24, and the adjacent, AC, is 10. We can plug those numbers in:

$tan(c) = \frac{24}{10} = \frac{12}{5}$

4 0

2 years ago