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ohaa [14]
3 years ago
13

22 + 14x = 14x + 22 Is this Commutative, Distributive, or Associative

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
6 0

Answer:

I think the answer is Associative.

Step-by-step explanation:

Leni [432]3 years ago
6 0

That's <u>Commutative</u> (a + b = b + a)

I hope Can to Help You ^_^

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What is the probability of first drawing a red card, then a face card, and then a black card? Do not round your intermediate com
lozanna [386]

Answer:

 [ 26 / 425 ] ≈ 0.0612

Step-by-step explanation:

Solution:-

- First we will describe the standard deck of 52 cards in terms of black, red and face cards found in a standard deck

- Following is a table of distribution of colored and face card found in a standard deck:

                 Type                   Number of cards

                 1 - 10                                40

                 Black                               26

                 Red                                 26

                 Face                                12

- The numerical cards from digit ( 1 to 10 ) are found in all 4 suits ( Clubs, Diamonds, Spades, and Hearts ). Hence, 10 x 4 = 40

- The entire deck is split in two colors ( Red and Black ) equally. So, the number of Black and Red cards are = 52 / 2 = 26 cards.

- The face cards are of three types ( King, Queen and Jack ). These three face cards are found in each of the 4 suits. Hence, Total number of face cards are = 4 * 3 = 12

- We will now consider the probabilities asscociated with each type. We will define 3 events and write down their proability as expressed:

Event ( A ): First draw is a red card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 red card in a standard deck of 52 cards. Hence,

            p ( A ) = [ Number of red cards ] / [ Total cards in a deck ]

            p ( A ) = [ 26 ] / [ 52 ]

            p ( A ) = 1 / 2

- After we make the first draw of a red card. Our deck distribution is changed to Number of Red cards remaining = 25 and total deck now has 51 cards remaining.

- We will define the next event as:

Event ( B ): The second draw is a face card.

- The probability of this event can be determined with the help of the table given above. There are a total of 12 face cards in a standard deck of 52 cards which is now down to 51 cards. Hence,

            p ( B ) = [ Number of face cards ] / [ Total cards in a deck ]

            p ( B ) = [ 12 ] / [ 51 ]

            p ( B ) = 4 / 17

- After we make the first draw of a face card. Our deck distribution is changed to Number of Face cards remaining = 11 and total deck now has 50 cards remaining.

- We will define the next event as:

Event ( C ): The third draw is a black card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 black cards in the deck. The total number of cards are down to 50 cards only. Therefore,

            p ( C ) = [ Number of black cards ] / [ Total cards in a deck ]

            p ( C ) = [ 26 ] / [ 50 ]

            p ( C ) = 13 / 25

- The entire drawing process consists of 3 events which are dependent on each draw. However, for the overall event to occur i.e drawing a red card , then a face card, and then a black card. We will multiply all three outcomes as follows:

          p ( T ) = p ( A ) * p ( B ) * p ( C )

          p ( T ) = [ 1 / 2 ] * [ 4 / 17 ] * [ 13 / 25 ]

          p ( T ) =  [ 26 / 425 ] ≈ 0.0612

4 0
3 years ago
I'm pretty sure the answer is median, just need confirmation, has a picture. Please help! Thanks!!
anygoal [31]
It's a median you are right
8 0
3 years ago
Read 2 more answers
3/2 * (-5/8) what is the an
castortr0y [4]

Answer:

-15/16

Step-by-step explanation:

3/2 x (-5/8) = 12/8 x -5/8 = -60/64 = - 15/16

6 0
3 years ago
$2.99 picture frame: Markup 150%
Kitty [74]
A 150% markup of a picture frame that costs 2.99 would cost : 4.49
7 0
3 years ago
3. How many solutions does the system of equations have? 2x=-10y+ 6 and x+5y=3
ozzi

Answer:

<h2>3. Infinitely many</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}ax+by=c\\dx+ey=f\end{array}\right\\\\(1)\\\text{if}\ a=d,\ b=e,\ c=f,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=5\end{array}\right\\(2)\\\text{if}\ a=d,\ b=e,\ c\neq f,\ \text{then the system of equations has no solution}\\Example:\\\left\{\begin{array}{ccc}2x-3y=5\\2x-3y=-5\end{array}\right

(3)\\\text{if}\ a\neq d\ \text{or}\ b\neq e,\ \text{then the system of equations has infinitely many solutions}\\Example:\\\left\{\begin{array}{ccc}x-3y=5\\2x-3y=5\end{array}\right

\text{We have:}\\\\\left\{\begin{array}{ccc}2x=-10y+6&\text{add 10y to both sides}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}2x+10y=6&\text{divide both sides by 2}\\x+5y=3\end{array}\right\\\left\{\begin{array}{ccc}x+5y=3\\x+5y=3\end{array}\right

4 0
3 years ago
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