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weeeeeb [17]
2 years ago
10

I need help with this question

Mathematics
1 answer:
Reika [66]2 years ago
6 0

Answer:

A) is 1/25

Step-by-step explanation:

Slope is rise over sun, hence... 2/50 (rise/run or length)

Then you simplify... 1/25

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What is the value of n?<br><br> –2n – 16 = 4n + 8
Anit [1.1K]

Answer:

-4=n

Step-by-step explanation:

-24=6n

-24/6=n

-4=n

7 0
3 years ago
Solve for x in the equation.
labwork [276]

Answer:

The solution is \displaystyle x=1\pm \sqrt{47}. Fourth option

Explanation:

Solve for x:

2x^2+3x-7=x^2+5x+39

Move all the terms from the right to the left side of the equation, a zero in the right side:

2x^2+3x-7-x^2-5x-39=0

Join all like terms:

x^2-2x-46=0

The general form of the quadratic equation is:

ax^2+bx+c=0

Solve the quadratic equation by using the formula:

\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

In our equation: a=1, b=-2, c=-46

Substituting into the formula:

\displaystyle x=\frac{-(-2)\pm \sqrt{(-2)^2-4(1)(-46)}}{2(1)}

\displaystyle x=\frac{2\pm \sqrt{4+184}}{2}

\displaystyle x=\frac{2\pm \sqrt{188}}{2}

Since 188=4*47

\displaystyle x=\frac{2\pm \sqrt{4*47}}{2}

Take the square root of 4:

\displaystyle x=\frac{2\pm 2\sqrt{47}}{2}

Divide by 2:

\displaystyle x=1\pm \sqrt{47}

First option: Incorrect. The answer does not match

Second option: Incorrect. The answer does not match

Third option: Incorrect. The answer does not match

Fourth option: Correct. The answer matches exactly this option

8 0
2 years ago
How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution.
Nadya [2.5K]
The answer is B

15 L of pure water must be mixed with 10 L of a 25% acid solution to reduce it to a 10% acid solution
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3 years ago
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Pls help this is 7th grade math :(
diamong [38]

Answer:

1.5

Step-by-step explanation:

i seached it up on go ggle

8 0
3 years ago
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True or False?<br> k = 3 over 4 is a solution to the inequality 12k + 2 &lt; 12.
Kaylis [27]
The answer is false
...................................

4 0
3 years ago
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