Question

The volume of a solid right pyramid with a square base is V units3 and the length of the base is y units what is the height of the pyramid?

Answer 1

Formulas

V = (1/3)* pi*B*h

B = s*s which is one side of the square base multiplied by itself.

Givens

s = y

V = V

h = ??

Substitute

V = (1/3)s^2*h Multiply both sides by 3

3V = s^2 * h

3V / s^2 = h

But y = s

3V /y^2 = h

Answer 2

Answer: $h=\frac{3V}{y^{2} }$

Step-by-step explanation: The volume of a pyramid is equal to one-third the product of the area of the base and the height:

$V=\frac{1}{3}A*h$

In this case, the base is a square, so its area is:

A=y^2 where "y" is the lenght of the base edge

So isolating the height it would be:

$h=\frac{3V}{A}$

$h=\frac{3V}{y^{2} }$