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3 years ago

5

True or false? The hypotenuse is the shortest side of a right angled triangle

2 answers:

ehidna [41]3 years ago

8 0

Answer:

F to the A to the L to the S to the E

Step-by-step explanation:

common mafs

kicyunya [14]3 years ago

5 0

Answer:

false

Step-by-step explanation:

its the longest side opposite the 90 degree angle

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*place holder since picture has the work*

ira [324]

Answer:

A square.

Step-by-step explanation:

I plotted the points on Desmos and then connected them.

When connected, the lines form a square.

[Picture Below]

3 0

3 years ago

Macy is tutoring students in mathematics during her summer break. She charges $20 for a 30 minute session and $35 for an hour. T

Zanzabum

If she only had 1 hour sessions she had 8 sessions in the first week because if you do 35 times 8 you get 280.

7 0

3 years ago

Simplify: 6-4[3(2x+5)-4x]

Degger [83]

[- 12 - 8x +5 16x]+ 6

7 0

2 years ago

Read 2 more answers

A teacher places n seats to form the back row of a classroom layout. Each successive row contains two fewer seats than the prece

Alex_Xolod [135]

Answer:

The number of seat when n is odd $S_n=\frac{n^2+2n+1}{4}$

The number of seat when n is even $S_n=\frac{n^2+2n}{4}$

Step-by-step explanation:

Given that, each successive row contains two fewer seats than the preceding row.

Formula:

The sum n terms of an A.P series is

$S_n=\frac{n}{2}[2a+(n-1)d]$

$=\frac{n}{2}[a+l]$

a = first term of the series.

d= common difference.

n= number of term

l= last term

$n^{th}$ term of a A.P series is

$T_n=a+(n-1)d$

n is odd:

n,n-2,n-4,........,5,3,1

Or we can write 1,3,5,.....,n-4,n-2,n

Here a= 1 and d = second term- first term = 3-1=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=1 and d=2

$n=1+(t-1)2$

⇒(t-1)2=n-1

$\Rightarrow t-1=\frac{n-1}{2}$

$\Rightarrow t = \frac{n-1}{2}+1$

$\Rightarrow t = \frac{n-1+2}{2}$

$\Rightarrow t = \frac{n+1}{2}$

Last term l= n,, the number of term $=\frac{ n+1}2$ , First term = 1

Total number of seat

$S_n=\frac{\frac{n+1}{2}}{2}[1+n}]$

$=\frac{{n+1}}{4}[1+n}]$

$=\frac{(1+n)^2}{4}$

$=\frac{n^2+2n+1}{4}$

n is even:

n,n-2,n-4,.......,4,2

Or we can write

2,4,.......,n-4,n-2,n

Here a= 2 and d = second term- first term = 4-2=2

Let $t^{th}$ of the series is n.

$T_n=a+(n-1)d$

Here $T_n=n$ , n=t, a=2 and d=2

$n=2+(t-1)2$

⇒(t-1)2=n-2

$\Rightarrow t-1=\frac{n-2}{2}$

$\Rightarrow t = \frac{n-2}{2}+1$

$\Rightarrow t = \frac{n-2+2}{2}$

$\Rightarrow t = \frac{n}{2}$

Last term l= n, the number of term $=\frac n2$ , First term = 2

Total number of seat

$S_n=\frac{\frac{n}{2}}{2}[2+n}]$

$=\frac{{n}}{4}[2+n}]$

$=\frac{n(2+n)}{4}$

$=\frac{n^2+2n}{4}$

4 0

2 years ago

Use estimation to check the answer to this story problem.

Lelechka [254]

Here, the answer would be: 765 * 11 = 8415 [ About 8 thousands ]

In short, Your Answer would be Option C) <span>The answer should be about 8,000 yards. The student's answer is not correct.

Hope this helps!</span>

3 0

3 years ago

Read 2 more answers