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kvv77 [185]
3 years ago
11

Aman decleared that he will give 20% discount on each items

Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

Let be cost price =Rs.100

Then mark price =Rs.120

∴ Selling price =90% of 120

=

100

120×90

=Rs.108

Profit = Selling price− Cost price

=Rs.(108−100)=Rs.8

Profit % =

100

8×100

=8%

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you have to use intercept theorem, also known as Thales's theorem to slove this problem

7 0
2 years ago
Find the average value of the function f(x)=−4sin(x) on the interval [π2,3π2] and determine a number c in this interval for whic
Ber [7]

Answer:

Step-by-step explanation:

The average value theorem sets:

if f (x) is continuous in [a, b] and derivable in (a, b) there is a c Є (a, b) such that

\frac{f(b)-f(a)}{b-a}=f'(c) , where

f(a)=f(π/2)=-4*sin(π/2) = -4*1= -4

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\frac{4-(-4)}{(3\pi/2)-(\pi/2)}=f'(c)

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f'(c)=-4cos(c)=\frac{8}{\pi }\\c=acos(\frac{-2}{\pi })\\

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8 0
3 years ago
Recently, TWA reported an on-time arrival rate of 78.4%. Assume that a later random sample of 750 flights results in 630 that ar
WINSTONCH [101]

Answer:

Step-by-step explanation:

1. Null hypothesis: u <= 0.784

Alternative hypothesis: u > 0.784

2. Find the test statistics: z using the one sample proportion test. First we have to find the standard deviation

Using the formula

sd = √[{P (1-P)}/n]

Where P = 0.84 and n = 750

sd =√[{0.84( 1- 0.84)/750]}

sd=√(0.84 (0.16) /750)

SD =√(0.1344/750)

sd = √0.0001792

sd = 0.013

Then using this we can find z

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z =(0.056/0.013)

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The p value at 0.02 level of significance for a one tailed test with 4.3077 as z score and using a p value calculator is 0.000008254.

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5 0
3 years ago
How many 5-letter words can be made using exactly 5 of the letters from
kow [346]

The total number of ways by words are formed is 35 ways.

According to the statement

We have given that the 5 letters and we have to make word from them and the letters are repeated as equal to letters in given words.

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TEXAS and MEXICO

Here X = 2 and E = 2 and all other words are one time used words.

We can find possible ways by use of combination and permutation.

So,

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here 3 because three letters are not repeatable and 2 letters are repeated for 2 times.

So,

Total number of ways = 3C_{1} ^{5} + 2C_{2} ^{5}

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Total number of ways = 3(5) + 2(10)

Total number of ways = 15 + 20

Total number of ways = 35.

So, The total number of ways by letters are formed is 35 ways.

Learn more about combination and permutation here

brainly.com/question/11732255

#SPJ1

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