Use the cross product to find the orthogonal vector, solve the parametric equation to see at which (t) the point + orthogonal vector intersects the plane, the distance is (t) * norm of vector
Answer:
On the Y axis
Step-by-step explanation:
<span><span>tan^2</span>(x) is the answer.</span>
Does it want it in standard form e.ge 0.00002 = 2 x 10(to the power of) -5, or is that in m and it wants you to convert it to micrometres?
Both the points have a coordinate where y is -1, so the equation is simply -1
y=-1
however if you wanted to really show the working out, it looks like this:
y=mx+c
m=change in y/change in x
m=(-1-1)/(-5+0)=0
subsitute one of the coordinates into y=mx+c
-1=0+c
c=-1
so then y=-1
