Answer:
Change in sulfur oxide in the air = 
Step-by-step explanation:
Data provided in the question:
Relation between the amount of sulfur oxide in the air and the population as:
S² = 110P² + 20P + 600
Population growth rate, 
= 10 people per month
Now,
change in sulfur oxide with time i.e 
differentiating the given relation with respect to time 't'
we have
= 
+ 20
at P = 100 and = 10 people per month
we have
= 2 × 110 × 100 × 10 + 20
or
= 220020
or
= 
or
Change in sulfur oxide in the air =
Rewrite the decimal number as a fraction with 1 in the denominator
0.225=0.22510.225=0.2251
Multiplying by 1 to eliminate 3 decimal places, we multiply top and bottom by 103 = 1000
0.2251×10001000=2251000
Answer:
The amount of gold used in a 200 g 14 gold bracelet is 116 g.
Step-by-step explanation:
Since a 14 karat jewell is stated to have aproximally 58 % of it's weigh in gold we need to take the total weigh of the jewel in question and find that percentage of it's weigh. In order to find that percentage we'll first convert that number into a decimal, we do that by dividing it by 100, so we have 58% = 58/100 = 0.58 we can multiply this value by the weigh of the jewel to find the amount of gold used. So we have:
gold used = total weigh*0.58 = 200*0.58 = 116 g
First we have to find p(AnB)
P(A/B)=p(AnB)/p(A)
P(AnB)=p(A) x p(A/B)
P(AnB)=0.5 x 0.4 = 0.2
Then to find p(B)
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.5+p(B)-0.2
0.6=0.3+p(B)
P(B)=0.6-0.3=0.3
We are given with a circle and we need to find the <em>equation of the circle</em> , but first let's recall that , the equation of a circle with radius<em> 'r'</em> and centre at <em>(h,k) </em>is given by 
Now , here as as the circle cuts the +ve x-axis at (9,0) . So , it's radius is 9 units or the 2nd way is to measure the distance from centre of the circle to the point where the circle cuts the graph , as the centre is at Origin , so here <em>(h,k) = (0,0)</em> .Which means that the centre is located at the point whose coordinates are<em> (0,0)</em> which is also known as origin . Now , finding the equation of the circle :-
<em>This is the required equation of Circle</em>
