Answer: Option (B) is correct
Explanation:
Data analysis is known as a process or technique of cleansing, inspecting, transforming and also modeling data with the aim or goal of discovering useful and vital information, briefing conclusions and thus finally supporting decision-making. It tends to have multiple approaches and facets, encompassing or enclosing diverse methods under several names, and thus is used in several different science, business, and dismal science domains.
Answer:
an immediate.
Explanation:
It is because of the instruction encoding and decoding.Intel which make these instructions decided not include instructions which provide no real advantage. MOV segment register is one of them because segment register need not to be changed very often.This saves the space in instruction encoding.
Answer and Explanation:
Given data:
Distance (D) = 40 KM
Speed of light in the fiber =Distance/ speed of light in the fiber
a) Delay (P) = Distance/ speed of light in the fiber
= (40,000 Meters/2×108 m/s)
=( 40×103 Meters/2×108 m/s)
Propagation delay (P) = 0.0002 seconds or 200 microseconds
b)
if propagation delay is 0.0002 Seconds roundup trip time (RTT) will be 0.0004 Seconds or 400 micro Seconds
Essentially since transmission times and returning ACKs are insignificant all we really need is a value slightly greater than 0.0004 seconds for our timeout value.
c)
The obvious reasons would be if the data frame was lost, or if the ACK was lost. Other possibilities include extremely slow processing on the receive side (late ACK).
Or Extremely Slow Processing of the ACK after it is received back at the send side.
Answer:
c. double triple(float n) { return (3 * n); }
Explanation:
In option a print is used to print integer.While printf is used in C to print something.
In option b there is no * operator between s s s it should be s*s*s.So it will give error.
In option d there is also no multiply operator * in between 3.14 2 r it should be 3.14*2*r.
So we can say that option c is error free.
Answer:
a)
#include <iostream>
using namespace std;
int main() {
bool a,b,c;
cin>>a>>b;
if(a^b)//X-OR operator in C++.
c=true;
else
c=false;
cout<<c;
return 0;
}
b)
#include <iostream>
using namespace std;
int main() {
bool a,b,c,d;
cin>>a>>b>>c;
if((a^b)^c)//X-OR operator in C++.
d=true;
else
d=false;
cout<<d;
return 0;
}
Explanation:
The above written programs are in C++.There is an operator (^) called X-OR operator in C++.It returns true if the number of 1's are odd and returns false if the number of 1's are even.
In the if statement I have user X-OR operator(^) to find the result and storing the result in another boolean variable in both the questions.
