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VashaNatasha [74]
3 years ago
11

A researcher randomly surveyed a sample of high school students in a town to find out which career area they were most intereste

d in pursuing. This table shows the results of the sample. The town has a total of 1000 high school students.
Art Science Finance Health Law Education
26 24 16 21 18 20
Based on this sample, how many high school students in the school are predicted to be most interested in pursuing a career in health?

Enter your answer in the box.

​
​

Mathematics
2 answers:
viktelen [127]3 years ago
7 0
Total of students sampled:
26 + 24 + 16 + 21 + 18 + 20 = 125 total
 21 picked health so 21 / 125 = 0.168 of the students picked health
 multiply that by total students:
1000 * 0.168 = 168 total students will pick health


Ugo [173]3 years ago
5 0
168 is the correct answer

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Find the area of the square with a side length of 8 ft.
FrozenT [24]

Answer:

The area of square is 64ft².

Step-by-step explanation:

Given that all sides of a square are equal. So you have to apply the formula for area of square :

area = length \times width

let \: length = 8 \\ let \: width = 8

area = 8 \times 8

area = 64  \: {ft}^{2}

7 0
2 years ago
Read 2 more answers
Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total s
garri49 [273]

Answer

a. The expected total service time for customers = 70 minutes

b. The variance for the total service time = 700 minutes

c. It is not likely that the total service time will exceed 2.5 hours

Step-by-step explanation:

This question is incomplete. I will give the complete version below and proceed with my solution.

Refer to Exercise 3.122. If it takes approximately ten minutes to serve each customer, find the mean and variance of the total service time for customers arriving during a 1-hour period. (Assume that a sufficient number of servers are available so that no customer must wait for service.) Is it likely that the total service time will exceed 2.5 hours?

Reference

Customers arrive at a checkout counter in a department store according to a Poisson distribution at an average of seven per hour.

From the information supplied, we denote that

X= Customers that arrive within the hour

and since X follows a Poisson distribution with mean \alpha = 7

Therefore,

E(X)= 7

& V(X)=7

Let Y = the total service time for customers arriving during the 1 hour period.

Now, since it takes approximately ten minutes to serve each customer,

Y=10X

For a random variable X and a constant c,

E(cX)=cE(X)\\V(cX)=c^2V(X)

Thus,

E(Y)=E(10X)=10E(X)=10*7=70\\V(Y)=V(10X)=100V(X)=100*7=700

Therefore the expected total service time for customers = 70 minutes

and the variance for serving time = 700 minutes

Also, the probability of the distribution Y is,

p_Y(y)=p_x(\frac{y}{10} )\frac{dx}{dy} =\frac{\alpha^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-\alpha } \frac{1}{10}\\ =\frac{7^{\frac{y}{10} } }{(\frac{y}{10})! }e^{-7 } \frac{1}{10}

So the probability that the total service time exceeds 2.5 hrs or 150 minutes is,

P(Y>150)=\sum^{\infty}_{k=150} {p_Y} (k) =\sum^{\infty}_{k=150} \frac{7^{\frac{k}{10} }}{(\frac{k}{10})! }.e^{-7}  .\frac{1}{10}  \\=\frac{7^{\frac{150}{10} }}{(\frac{150}{10})! } .e^{-7}.\frac{1}{10} =0.002

0.002 is small enough, and the function \frac{7^{\frac{k}{10} }}{(\frac{k}{10} )!} .e^{-7}.\frac{1}{10}  gets even smaller when k increases. Hence the probability that the total service time exceeds 2.5 hours is not likely to happen.

3 0
2 years ago
Why are probability and statistics important?
Anestetic [448]

Answer:

Studying probability and statistics will allow you to see the world from an entirely different perspective, since the subjects will give you the tools to model and analyze situations, which involve uncertainty.

7 0
3 years ago
What are the factors of the equation x 2 - 5x + 6?
xxTIMURxx [149]

Answer:

(x-3)(x-2)

Step-by-step explanation:

x^2 -5x+6

What two numbers multiply to 6 and add to -5

-3 * -2 = 6

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(x-3)(x-2)

7 0
2 years ago
Find the mean absolute deviation
pantera1 [17]
First find the mean (sum divided by number of values)
4+5+8+10+15=42
42/5=8.4
Then find the difference between each of the numbers and the mean.
4.4, 3.4, 0.4, 1.6, 6.6
Then find the mean of those values.
4.4+3.4+0.4+1.6+6.6=16.4
16.4/5=3.28
Final answer: 3.28
6 0
3 years ago
Read 2 more answers
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