7/8 minus1/4 minus 1/2
7/8 - 1/4 - 1/2 =
(1 × 7)/(1 × 8) - (2 × 1)/(2 × 4) - (4 × 1)/(4 × 2) =
7/8 - 2/8 - 4/8 =
(7 - 2 - 4)/8 =
1/8
the answer is 1/8
Whats the question? ill try to help
Let any integer be represented by x.
Then, the consecutive integer (the number that follows) should be x+1.
The statement wants us to prove;
(x+1)²-x²=x+(x+1) <-- solve left hand side
x²+x+x+1²-x²
2x+1 (solution for left hand side)
Now solve for right hand side.
x+(x+1)= 2x+1
As noticed, the LHS=RHS (left hand side= right hand side), therefore, the difference of squared consecutive numbers subtracted is equal to the sum of the two integers.
Hope I helped :)
