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sashaice [31]
3 years ago
7

On a team 5 girls and 2 boys scored a total of 41 points. The difference between the number of points scored by the 5 girls and

the number of points scored by the
2 boys is 29. Each girl scored the same number of points and each boy scored the same number of points. Find the number of points scored by each girl and each
boy
Each girl scored points
Mathematics
1 answer:
kolbaska11 [484]3 years ago
6 0

Step-by-step explanation:

Let x be the number of points the 5 girls scored.

=> 41 - x is the number of points the 2 boys scored.

We have x + 29 = 41 - x or x - 29 = 41 - x.

=> 2x = 12 or 2x = 70

=> x = 6 or x = 35

We reject x = 6 as 6 is not a multiple of 5. (Each girl would have scored 1.2 points which is absurb)

So x = 35, each girl scored 35/5 = 7 points.

=> 41 - (35) = 6, each boy scored 6/2 = 3 points.

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Find three consecutive integers such that the sum of the first and twice the second is 110 minus three times the third
Serggg [28]

First off, consecutive integer and  can be written as n, n+1 and n+2

(try putting a number in for n if it does not make sense yet)

The sum of the first and twice the second would be n+2(n+1)

So, our equation becomes

n+2(n+1)=110-3(n+2)

n+2n+2=110-3n-6

3n+2=104

6n=102

n=17

so, our three term are 17,18 and 19


7 0
3 years ago
12,14,18,26,42 what are the next 2 numberso in the sequence
maw [93]
12 to 14=2
14 to 18=4
18 to 26=8
26 to 42=16
The difference between each number doubles each time.
Therefore the next 2 numbers should be 74 and 138.
16x2=32, 42+32=74
32x2=64, 74+64=138
4 0
3 years ago
Read 2 more answers
HELP ASAP
Darya [45]

Answer:

C, 18.

Step-by-step explanation:

Since 24 divided by 8 is 3, which means that

8x3 = 24, then the amount of boys must be solved using the equation 6x3 which equals 18.

3 0
3 years ago
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Solve for y: 2(3y + 5) = 3(5y + 3).<br> The solution is y =<br> The solution is
lisov135 [29]

Answer:

y = \frac{1}{9}

Step-by-step explanation:

Given

2(3y + 5) = 3(5y + 3) ← distribute parenthesis on both sides

6y + 10 = 15y + 9 ( subtract 6y from both sides )

10 = 9y + 9 ( subtract 9 from both sides )

1 = 9y ( divide both sides by 9 )

\frac{1}{9} = y

4 0
4 years ago
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In the following sequence of numbers each number has one more "1" than the preceding number: 1, 11, 111, 1111, 11111, ... . What
STatiana [176]

Answer: 2

Step-by-step explanation:

we have the sequence 1, 11, 111, 1111 and so on.

We can write this sequence as:

A0 = 1

An = A(n -1) + 10^n.

such that:

A1 = A0 + 10^1 = 1 + 10 = 11.

A2 = 11 + 10^2 = 11 + 100 = 111.

and we want to find the tens digit of the sum of the first 30 terms.

ok, in the 30 terms, in the units digit we have a 1, so we have:

30*1 = 30

we leave the zero and the 3 goes to the tens place.

For the tens place. the first term does not aport nothing, and the other 29 terms aport a 1, so we have:

tens = 3 + 29*1 = 32

then we leave a 2 here and pass a 3 to the hundreds place.

But we already answered the question, the tens digit in the sum of the first 30 numbers of the sequence is 2.

4 0
3 years ago
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