Answer and Explanation:
The journal entries are shown below;
On March 1
Cash A/c $303,500
To Common Stock $3 Par value (44,500 × $3) $133,500
To Paid in capital in excess of par value $170,000
(Being the common stock issued is recorded)
On April 1
Cash $74,000
To Common Stock, no par value $74,000
(Being the common stock issued is recorded)
On April 6
Inventory $43,000
Machinery $155,000
To Common Stock (2,400 ×$20) $48,000
To Notes payable $93,000
To Paid in capital in excess of par value $57,000
(Being the shares are issued)
Answer:
Charles is classified in the adopter category called "Latecomers"
Explanation:
Latecomers are traditional consumers. For them, buying a new product brings a feeling of extreme psychological discomfort. They do not like news, even flee from it, and consider it immature to buy an innovative article in the market.
Latecomers represent 16% of consumers, are insecure to adopt new things, do not like to try new things and do not follow fads. Being traditionalists, they always perform the same way and only adopt innovation when there is no other alternative. Like Charles, who only bought the color TV because his old tv stopped working.
Answer: D. $2870000
Explanation:
Consolidated Assets are the assets that a company owes whether directly or indirectly through a subsidiary which will then be shown on the consolidated balance sheet of the company.
From the information given, the amount of total consolidated net assets will be calculated as:
= ($34000 × 35) + $700,000 + $980,000
= $1,190,000 + $700,000 + $980,000
= $2,870,000
Answer:
Therefore after 16.26 unit of time, both accounts have same balance.
The both account have $8,834.43.
Explanation:
Formula for continuous compounding :
P(t)= value after t time
= Initial principal
r= rate of interest annually
t=length of time.
Given that, someone invested $5,000 at an interest 3.5% and another one invested $5,250 at an interest 3.2% .
Let after t year the both accounts have same balance.
For the first case,
P= $5,000, r=3.5%=0.035
For the second case,
P= $5,250, r=3.5%=0.032
According to the problem,
Taking ln both sides
Therefore after 16.26 unit of time, both accounts have same balance.
The account balance on that time is
=$8,834.43
The both account have $8,834.43.
