If the length of rectangular school hall is 4 times the width and the perimeter be 55m, then the length is 22m and the width of the school hall be 5.5m.
Given that the length of rectangular school hall is 4 times the width.
We are required to find the length and breadth of the rectangle which has the length be 4 times the width.
Perimeter of rectangle is the sum of all the length and breadth of that rectangles.
Perimeter of rectangle is given as 55m
Perimeter=2(L+B)
let the width of rectangle be x.
Length of that rectangle be 4x.
According to question,
2(x+4x)=55
2*5x=55
10x=55
x=55/10
x=5.5 m
Width be 5.5 m.
Length of rectangle be 4*5.5=22m.
Hence if the length of rectangular school hall is 4 times the width then the length is 22m and the width of the school hall be 5.5m.
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Answer:
Step-by-step explanation:
The composite figure consists of a square prism and a trapezoidal prism. By adding the volume of each, we obtain the volume of the composite figure.
The volume of the square prism is given by , where is the base length and is the height. Substituting given values, we have:
The volume of a trapezoidal prism is given by , where and are bases of the trapezoid, is the length of the height of the trapezoid and is the height. This may look very confusing, but to break it down, we're finding the area of the trapezoid (base) and multiplying it by the height. The area of a trapezoid is given by the average of the bases () multiplied by the trapezoid's height ().
Substituting given values, we get:
Therefore, the total volume of the composite figure is (ah, perfect)
Alternatively, we can break the figure into a larger square prism and a triangular prism to verify the same answer:
Answer:
y=2x+9
Step-by-step explanation:
Answer:
B) 3/6
c) 3/6
I hope this is the answer
(2h – 3)(3h + 4) is the same thing as
2h(3h + 4) - 3(3h + 4)
6h^2 + 8h - 9h - 12
6h^2 - h - 12
Answer B.