The first thing we are going to do is draw a diagram of the situation to help us to solve the situation.
We an draw tow similar triangle between the length of the shadows and the height of the stick and the pole.
Since <span>meter stick has a length of 1 meter, the height of our smaller triangle is 1 meter. Let </span>

be height of of the pole. Since both triangles are similiar we can establish a proportion between their corresponding sides and solve for

:



We can conclude that the pole is
4.04 meters tall.
Strength [is proportional to] d^2
strength1/(d1)^2 = strength2/(d2)^2
800kg/(2cm)^2 = strength2/(3cm)^2
strength2 = 800 kg * (3 cm)^2/(2 cm)^2
strength2 = 800 kg * 3^2/2^2
strength2 = 800 kg * 9/4
strength2 = 1800 kg
In order to answer this question let's suppose,
Joe is x miles from the beginning and y miles from the end. These assumptions are necessary to answer further:
Now,
x=2y
x+y=30
plugging in x=2y in the above equation
2y+y=30
3y=30
y=10
Hence, according to our calculations, Joe has to hike 10 miles further

now, you're asked to use it when ln(1.38), which is just another way of saying x = 1.38
so set x = 1.38 and see what "y" is