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Helen [10]
3 years ago
6

Q4. A simple random sample of size n=180 is obtained from a population whose size=20,000 and whose population proportion with a

specified characteristic is p=0.45. Determine whether the sampling distribution has an approximate normal distribution. Show your work that supports your conclusions.
Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Answer:

np = 81  , nQ = 99

Step-by-step explanation:

Given:

X - B ( n = 180 , P = 0.45 )

Find:

Sampling distribution has an approximate normal distribution

Computation:

nP & nQ ≥ 5

np = n × p

np = 180 × 0.45

np = 81

nQ = n × (1-p)

nQ = 180 × ( 1 - 0.45 )

nQ = 99

Therefore, sampling\ distribution\ has\ an\ approximately\ normal\ distribution.

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number of blue beads in pattern 5 will be 15 ( increasing by 3 )

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nth term for blue =  3 + 3(n - 1)   - as above ,arithmetic.

Total beads in pattern 45 is

No. red beads in pattern 26   = 4  + 2(26-1)  = 4 + 50 = 54
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Total number of beads in pattern 45 is:-

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3 years ago
Lucy reads 72 chapters of a book in 8 hours. What is her rate in chapters per hour?
Sophie [7]
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8 0
3 years ago
Read 2 more answers
I dont understand please help
DiKsa [7]

2 \frac{1}{2}+(-2\frac{1}{4})

This is equal to:

2\frac{1}{2}-2\frac{1}{4}

When you add a negative number, it turns into subtraction.

First, I would change it to mixed numbers:

\frac{5}{2}-\frac{9}{4}

Now, you need to change the denominators to make sure they are the same on both fractions. I changed the first fraction's denominator to 4 so they match. You can do this by multiplying the numerator by 2:

\frac{10}{4}-\frac{9}{4}

Now, you simply subtract:

10-9=1

1/4 is your answer.

I hope this helps :)

3 0
3 years ago
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38% is being subtracted from your total, so you can do this:

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3 years ago
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Ilya [14]
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3 years ago
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