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myrzilka [38]
4 years ago
10

What is the length of the conjugate axis?

Mathematics
2 answers:
Lana71 [14]4 years ago
5 0
ANSWER

The length of the conjugate axis is 6 units.

EXPLANATION

The given hyperbola has equation:

\frac{(x - 1)^{2} }{25} - \frac{ {(y + 3)}^{2} }{9} = 1

We can rewrite this equation in the form:

\frac{(x - 1)^{2} }{ {5}^{2} } - \frac{ {(y + 3)}^{2} }{ {3}^{2} } = 1

We compare this equation to:

\frac{(x - h)^{2} }{ {a}^{2} } - \frac{ {(y - k)}^{2} }{ {b}^{2} } = 1

This implies that;

a = 5

and

b = 3

The length of the conjugate axis of a hyperbola is

= 2b

Substitute b=3 to obtain;

= 2 \times 3

= 6
iogann1982 [59]4 years ago
5 0

Answer:

the other person is right, the answer is 6

Step-by-step explanation:

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1 year ago
Select the correct answer. The capacity in cubic feet of a cylindrical silo is given by the function C(x), where x is the radius
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Answer:

C. H(x) = 2x+6

Step-by-step explanation:

Volume of the cylindrical silo = Area of its circular base × Height

Volume of the cylindrical silo = πr²×H

If the area of the circular base of the silo is given by the function A(x), the volume is given by C(x) and the height is given by H(x), the formula can be expressed as;

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The height of the cylindrical silo will be;

H(x) = C(x)/A(x)

Given C(x) = 6.28x³ + 18.84x² and

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H(x) = 6.28x³ + 18.84x²/3.14x²

H(x) = x²(6.28x+18.84)/3.14x²

H(x) = (6.28x+18.84)/3.14

H(x) = 3.14(2x+6)/3.14

H(x) = 2x+6

Hence, the function, H(x) that represents the height of the silo is 2x+6.

4 0
4 years ago
Carter is handing out Valentine’s Day cards to his friends. He has 8 Batman cards, 12 Superman cards, and 5 captain America card
Gemiola [76]

Answer:

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Step-by-step explanation:

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Answer:

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\frac{X}{6}\geq 20-5\\\frac{X}{6}\geq 15\\X\geq 6*15\\X\geq 90

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4 years ago
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Answer:

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Step-by-step explanation:

3 numbers x, y, z

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check: 23 + 32 + 69 = 124

8 0
4 years ago
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