You do 53 can go into 66 1 time so put
The answer is 3x^2 + 19x - 12.
Answer:
the median of this data is 12
Answer:
![\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20%5C%20%5C%20%5C%20%5Cdfrac%7B18%7D%7B%28x-7%29%28x%2B12%29%28x%2B30%29%7D%20%5C%20%5C%20%5C%20%7D)
Step-by-step explanation:
hello,
first of all we will study the quadratic expressions
we can write that, (the different answers provide good clues :-) )
![x^2+5x-84=(x-7)(x+12)](https://tex.z-dn.net/?f=x%5E2%2B5x-84%3D%28x-7%29%28x%2B12%29)
and
![x^2+23x-210=(x-7)(x+30)](https://tex.z-dn.net/?f=x%5E2%2B23x-210%3D%28x-7%29%28x%2B30%29)
so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write
![\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}](https://tex.z-dn.net/?f=%5Cdfrac%7B1%7D%7Bx%5E2%2B5x-48%7D-%5Cdfrac%7B1%7D%7Bx%5E2%2B23x-210%7D%3D%5Cdfrac%7B1%7D%7B%28x-7%29%28x%2B12%29%7D-%5Cdfrac%7B1%7D%7B%28x-7%29%28x%2B30%29%7D%5C%5C%5C%5C%3D%5Cdfrac%7B%28x%2B30%29%20-%28x%2B12%29%7D%7B%28x-7%29%28x%2B12%29%28x%2B30%29%7D%3D%5Cdfrac%7Bx%2B30-x-12%7D%7B%28x-7%29%28x%2B12%29%28x%2B30%29%7D%5C%5C%5C%5C%3D%5Cdfrac%7B18%7D%7B%28x-7%29%28x%2B12%29%28x%2B30%29%7D)
hope this helps