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Charra [1.4K]
4 years ago
10

99 Points!!!

Mathematics
2 answers:
nikitadnepr [17]4 years ago
7 0

Compare centers mean you need to compare the median of the two box plots.

Box 1: Median (Q2) = 40

Box 2: Median (Q2 is between 40 and 50 (40 < Q2 < 50)

So the center of box 2 is greater than center of box 1

Hope it helps.


Morgarella [4.7K]4 years ago
4 0

Answer:

the the center of "box" 2 is greater then the center of "box" 1

its bc the median in box 2 is greater thanthe first box

-Box 1's median is 40

-Box 2's median is somewhere between 45 and 53

~batmans wife dun dun dun...aka ~serenitybella

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Identify the surface area of the composite figure. HELP PLEASE!!
Novosadov [1.4K]

Answer:

Step-by-step explanation:

I've already done this question for you. You must be reposting it because the answer was not correct according to the way the computer was programmed to get the answer. I can only think that you don't count the interface between the cube and the larger figure at all. So let's do it that way.

Start with the cube.

The formal equation is Area = 5 * s^2

It has 5 equal sides each one measuring 3 * 3

Area = 5 * 3^2 =                                                                              45

Now go to the other figure

The front and back face measure 14*6*2                                = 168

Left and Right Sides are 2 * 6 * 8                                                 96

Top and Bottom              2 * 14 *8                                              224

Don't count the base of the cube at all so subtract 3*3             -9

Total                                                                                             524

If that does not work, please leave a note at the bottom of this question.

5 0
4 years ago
A. 5pi/6<br> B. 8pi/6<br> C. 3pi/6<br> D. 13pi/6
MakcuM [25]

Answer:

Step-by-step explanation:

8 0
3 years ago
Fine the area of the shape below PLSSS HELP
Rudiy27

Answer:

58 yds (squared yards) 6 × 7 = 42, 4 × 4 = 16; 42 + 16 = 58

hope this helps!

8 0
3 years ago
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the number of buckets of paint n needed to paint a wall varies jointly with the total area a and the thickness t of the wall, an
Nat2105 [25]
The number of buckets is directly proportional to the area and the thickness of the wall and inversely proportional to the amount of paint. Mathematically, we can write:

n = k · (a · t) / p

where k is the proportionality constant which we do not know.

We can calculate k with the given data: 5 2-gallon buckets, area of 100 square feet and thickness 3 inches:

k = (n · p) / (<span>a · t)
   = (5 </span>· 2) / (100 · 3) = 0.0333

Now that we know the constant, we can calculate the area that can be painted with 8 2-gallon buckets if the thickness is 6 inches:

a =  (n · p) / (k<span> · t)
   = (8 </span>· 2) / (0.0333 · 6)
   = 80 ft²

Please, note that we made sure to have the exact same units of measurements than the previous case.

Therefore, the correct answer is an area of 80 ft².
4 0
3 years ago
I need help plzzz
Veronika [31]

Answer:

Yes I think so

Step-by-step explanation:

3 0
3 years ago
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