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3 years ago

99 Points!!!

Mathematics

2 answers:

nikitadnepr [17]3 years ago

7 0

Compare centers mean you need to compare the median of the two box plots.

Box 1: Median (Q2) = 40

Box 2: Median (Q2 is between 40 and 50 (40 < Q2 < 50)

So the center of box 2 is greater than center of box 1

Hope it helps.

Morgarella [4.7K]3 years ago

4 0

Answer:

the the center of "box" 2 is greater then the center of "box" 1

its bc the median in box 2 is greater thanthe first box

-Box 1's median is 40

-Box 2's median is somewhere between 45 and 53

~batmans wife dun dun dun...aka ~serenitybella

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$S^2$ = sample variance

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First we find the mean of their salaries.

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So, $\bar{x}=31$

Using the formula for variance ,

$S^2=\frac{(33-31)^2}{4-1}+\frac{(31-31)^2}{4-1}+\frac{(24-31)^2}{4-1}+\frac{(36-31)^2}{4-1}\\\\ S^2=\frac{4}{3} + \frac{0}{3} + \frac{49}{3} + \frac{25}{3} \\\\S^2= \frac{4+49+25}{3}\\\\S^2=\frac{78}{3} \\\\S^2=26$

Therefore, for given sample of salaries of four employees, the variance of their salaries is: 26 thousands of dollars

Learn more about the variance here:

brainly.com/question/13673183

#SPJ4

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