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barxatty [35]
3 years ago
12

Which equation can be used to solve for the value of n if 2 + n = 12?

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0
N=12-2 is the answer of this question
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6th grade math help me, please:)))
Lesechka [4]

Step-by-step explanation:

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5 0
3 years ago
Use the replacement set {3, 4, 9} to find the solution of the equation below.<br> 3n−18=9
Mrac [35]

Answer:

n=9

Step-by-step explanation:

3n-18=9

3n+18= +18

3n=27

3(9)=27

n=9

5 0
3 years ago
How do i solve this question 58−(14)2
Naily [24]

Answer:

PEMDAS RULE

Step-by-step explanation:

STEP one is multiplication 58-14x2=58-28

STEP two is subtraction 58-28=30

Parenthesis

Exponent

Multiplication

Division

Addition

Subtract

3 0
3 years ago
Read 2 more answers
A student downloaded a new game on her phone that was recommended by her friend. She wanted to show her friend how good
anygoal [31]

Answer:

a. 587

b. 543

Step-by-step explanation:

a. Mean = sum / number of numbers

To find the sum, we can add the numbers up.

432 + 543 + 348 + 788 + 823 = 2934

There are 5 numbers. Our mean is thus

2934/5 = 586.8, or 587 when rounding up. We round up because we have a .8 at the end, and 8 ≥ 5

b. To find the median, we first must order the numbers. The numbers ordered are this:

348 ,  432 , 543 , 788 , 823

To find the median, we can cross off one number on each side until we are left with one or two numbers.

348 ,  432 , 543 , 788 , 823

cross out one number from each endpoint

432 , 543 , 788

cross out one number from each endpoint

543

7 0
2 years ago
Determine whether or not the vector field is conservative. if it is, find a function f such that f = ∇f. if the vector field is
amm1812
\dfrac{\partial f}{\partial x}=3y^2z^3\implies f(x,y,z)=3xy^2z^3+g(y,z)

\dfrac{\partial f}{\partial y}=6xyz^3+\dfrac{\partial g}{\partial y}=6xyz^3
\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)

\dfrac{\partial f}{\partial z}=9xy^2z^2+\dfrac{\mathrm dh}{\mathrm dz}=9xy^2z^2
\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C

\implies f(x,y,z)=3xy^2z^3+C

The potential function exists, so \mathbf f is indeed conservative.
7 0
3 years ago
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