Answer:
Step-by-step explanation:
A quadratic function is given to us . And we need to fill out the table by using the function . The given function is ,
Here we need to substitute the different values of x , to get the different values of y.
<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>3</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Put </u><u>x </u><u>=</u><u> </u><u>-</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Put</u><u> </u><u>x </u><u>=</u><u> </u><u>-</u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

<u>Put </u><u>x </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Put </u><u>x </u><u>=</u><u> </u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>
<u>Put </u><u>x </u><u>=</u><u> </u><u>3 </u><u>:</u><u>-</u><u> </u>
<u>Final </u><u>table</u><u> </u><u>:</u><u>-</u><u> </u>

Im pretty sure its 18 unless im reading it wrong
Combine the fractions by finding a common denominator.
10r+9/r(r+3)
Answer:
![\sf A) \ (-4, \ 0) \ and \ \ [\dfrac{5}{2} , \ 0]](https://tex.z-dn.net/?f=%5Csf%20A%29%20%5C%20%28-4%2C%20%5C%200%29%20%5C%20and%20%5C%20%5C%20%20%5B%5Cdfrac%7B5%7D%7B2%7D%20%2C%20%5C%200%5D)
Explanation:
Given function: f(x) = -2x² - 3x + 20
To find the x-intercepts of a function, f(x) = 0
=================
-2x² - 3x + 20 = f(x)
-2x² - 3x + 20 = 0
-2x² - 8x + 5x + 20 = 0
-2x(x + 4) + 5(x + 4) = 0
(-2x + 5) (x + 4) = 0
-2x + 5 = 0, x + 4 = 0
-2x = -5, x = -4
x = -5/-2,x = -4
x = 5/2, x= -4
Coordinates: (-4, 0), (5/2, 0)