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Vaselesa [24]
3 years ago
14

How many are 8 raised to 3 ???​

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
7 0
512 hope it’s right
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An exponential function f(x) = ab^xpasses through the points (0, 2) and (3, 54). What are the values of a and
Vsevolod [243]

Answers:

a = 2

b = 3

=======================================================

Explanation:

Plug in x = 0 and y = 2 to find that

y = a*b^x

2 = a*b^0

2 = a*1

2 = a

a = 2

Then plug in x = 3 and y = 54 to determine the value of b

y = a*b^x

y = 2*b^x

54 = 2*b^3

2b^3 = 54

b^3 = 54/2

b^3 = 27

b = (27)^(1/3)

b = 3

So we have y = a*b^x update to y = 2*3^x

7 0
3 years ago
How many counters would you place in the five frame to show the number
Leviafan [203]
Assuming the five frame is for the number five (5) then place 5 counters in the frame.
7 0
3 years ago
Given a triangle MTN, prove that
cupoosta [38]

Answer:

<em></em>\angle m + \angle t + \angle n = 180<em></em>

<em></em>

Step-by-step explanation:

Required

Show that:

\angle m + \angle t + \angle n = 180^o

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

In the attached triangle, the two angles beside \angle m are alternate to \angle t and \angle n

i.e.

\angle 1 = \angle t

\angle 2 = \angle n

Using angle on a straight line theorem, we have:

\angle 1 + \angle m + \angle 2 = 180

Substitute values for (1) and (2)

\angle t + \angle m + \angle n = 180

Rewrite as:

<em></em>\angle m + \angle t + \angle n = 180<em> -- proved</em>

5 0
3 years ago
PLEASE HELP QUICKLY: (FIRST ANSWER GETS BRAINLIEST)
kodGreya [7K]

Answer:

Buy the batteries and stereo online:  

4.99*2= $9.98 +$90 = $99.98  

6.99-5.00 = $1.99  

99.98+1.99=$101.97  

3Cds in store  

7.97*3= $23.85  

5% tax = 1.19  

10% off = 2.39  

$23.85 - $1.19= $22.66  

22.66 + 101.97= $124.63  

All in store:  

12+100+23.85= 135.85 - 6.45 = $129.40  

All online:  

9.98 + 90 + 26.85= 126.85 +$1.99 = 128.84

<u><em>(CREDIT: Hussain514)</em></u>

8 0
3 years ago
in a city school of 1,200 students, 40% of the students are on the honor roll, 60% have a part-time job, and 22% are on the hono
Alexus [3.1K]
Let
A = event that the student is on the honor roll
B = event that the student has a part-time job
C = event that the student is on the honor roll and has a part-time job

We are given
P(A) = 0.40
P(B) = 0.60
P(C) = 0.22
note: P(C) = P(A and B)

We want to find out P(A|B) which is "the probability of getting event A given that we know event B is true". This is a conditional probability

P(A|B) = [P(A and B)]/P(B)
P(A|B) = P(C)/P(B)
P(A|B) = 0.22/0.6
P(A|B) = 0.3667 which is approximate

Convert this to a percentage to get roughly 36.67% and this rounds to 37%

Final Answer: 37%

4 0
3 years ago
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